Check the picture below.
![\bf A=\cfrac{h(a+b)}{2}\quad \begin{cases} A=20\\ a=6z-1\\ b=2z+3\\ h=z \end{cases}\implies 20=\cfrac{z[(6z-1)~+~(2z+3)]}{2} \\\\\\ 20=\cfrac{z(8z+2)}{2}\implies 20=\cfrac{2z(4z+1)}{2}\implies 20=z(4z+1) \\\\\\ 20=4z^2+z\implies 0=4z^2+z-20](https://tex.z-dn.net/?f=%5Cbf%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D%5Cquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D20%5C%5C%0Aa%3D6z-1%5C%5C%0Ab%3D2z%2B3%5C%5C%0Ah%3Dz%0A%5Cend%7Bcases%7D%5Cimplies%2020%3D%5Ccfrac%7Bz%5B%286z-1%29~%2B~%282z%2B3%29%5D%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0A20%3D%5Ccfrac%7Bz%288z%2B2%29%7D%7B2%7D%5Cimplies%2020%3D%5Ccfrac%7B2z%284z%2B1%29%7D%7B2%7D%5Cimplies%2020%3Dz%284z%2B1%29%0A%5C%5C%5C%5C%5C%5C%0A20%3D4z%5E2%2Bz%5Cimplies%200%3D4z%5E2%2Bz-20)
since the height is just a length unit, it can't be -2.3646.
The slope is 1/3
hope that help
Do you have a picture to go with it?
Solution for given equation -(5-(a+1)) = 9-(5-(2-3)) is a = 7
<u>Solution:
</u>
Need to determine solution of following equation’
-(5-(a+1)) = 9-(5-(2-3))
Means need to solve the above equation for "a"
On solving operation in most internal bracket we get
-(5-(a+1)) = 9- ( 5 – ( -1))
On opening inside brackets we get,
-(5 – a – 1 ) = 9 – ( 5 +1 )
On solving remaining brackets we get
-5 + a + 1 = 9 – 6
=> a – 4 = 3
=> a = 4 + 3 = 7
=> a = 7
Hence solution for given equation -(5-(a+1)) = 9-(5-(2-3)) is a = 7
Answer:
Sam sokey 0.5 hours biking and 3.5 hours walking
Step-by-step explanation:
Here, we want to know the number of hours spent walking and biking
Mathematically; distance = speed * time
Let the number of hours spent walking be x and the number of hours spent biking be y
Mathematically;
x + y = 3 •••(i)
distance spent walking = 4 * x = 4x miles
distance spent biking = 12 * y = 12y miles
4x + 12y = 20
divide through by 2
2x + 6y = 10 ••••••(ii)
From i , x = 4-y
Substitute this into ii
2(4-y) + 6y = 10
8 - 2y + 6y = 10
8 + 4y = 10
4y = 10-8
4y = 2
y = 2/4 = 0.5 hours
The number of hours spent walking = 4-0.5 = 3.5 hours
