All categories

3 years ago

Eldon started practicing piano at 7:45. He played scales for 1/6 of an hour popular songs for 2/5 an hour,

Mathematics

1 answer:

kolezko [41]3 years ago

5 0

Answer:

Stopped playing at 8:34

Step-by-step explanation:

Let's calculate his practice time in minutes. We know 60 mins = 1 hour

Now,

1/6th of an hour = 1/6 * 60 = 10 minutes

2/5th of an hour = 2/5 * 60 = 24 minutes

1/4th of an hour = 1/4 * 60 = 15 minutes

So, his practice time in total is:

10 + 24 + 15 = 49 minutes.

Now he started at 7:45, so he will end after 49 minutes, that would be:

8:34

You might be interested in

How I divide by negative?? I forgot completely

allochka39001 [22]

Answer:

I hope this helps. If I misunderstood the question let me know

Step-by-step explanation:

1. When dividing a negative by a negative, your answer would be positive.

2. When dividing a negative by a positive, your answer will be negative.

3. When dividing a positive by a negative,your answer will be negative.

3 0

2 years ago

Read 2 more answers

What is the definition of perfect cube and can you give an example

PilotLPTM [1.2K]

A perfect cube is a natural number in the form
${a}^{3} = a \times a \times a$
therefore
${1}^{3} = 1 \\ {2}^{3} = 8 \\ {3}^{3} = 27 \\ {4}^{3} = 64 \\ {5}^{3 } = 125 \\ . \\ . \\ .\\ .$
and also you can define it as any natural number who's third root is also a natural number for examble
$\sqrt[3]{1000} = 10$
so you can say that the tenth perfect cube is 1000

6 0

3 years ago

CALC- limits please show your method

gladu [14]

A. Factor the numerator as a difference of squares:

$\displaystyle\lim_{x\to9}\frac{x-9}{\sqrt x-3}=\lim_{x\to9}\frac{(\sqrt x-3)(\sqrt x+3)}{\sqrt x-3}=\lim_{x\to9}(\sqrt x+3)=6$

c. As $x\to\infty$ , the contribution of the terms of degree less than 2 becomes negligible, which means we can write

$\displaystyle\lim_{x\to\infty}\frac{4x^2-4x-8}{x^2-9}=\lim_{x\to\infty}\frac{4x^2}{x^2}=\lim_{x\to\infty}4=4$

e. Let's first rewrite the root terms with rational exponents:

$\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}$

Next we rationalize the numerator and denominator. We do so by recalling

$(a-b)(a+b)=a^2-b^2$
$(a-b)(a^2+ab+b^2)=a^3-b^3$

In particular,

$(x^{1/3}-x)(x^{2/3}+x^{4/3}+x^2)=x-x^3$
$(x^{1/2}-x)(x^{1/2}+x)=x-x^2$

so we have

$\displaystyle\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}\cdot\frac{x^{2/3}+x^{4/3}+x^2}{x^{2/3}+x^{4/3}+x^2}\cdot\frac{x^{1/2}+x}{x^{1/2}+x}=\lim_{x\to1}\frac{x-x^3}{x-x^2}\cdot\frac{x^{1/2}+x}{x^{2/3}+x^{4/3}+x^2}$

For $x\neq0$ and $x\neq1$ , we can simplify the first term:

$\dfrac{x-x^3}{x-x^2}=\dfrac{x(1-x^2)}{x(1-x)}=\dfrac{x(1-x)(1+x)}{x(1-x)}=1+x$

So our limit becomes

$\displaystyle\lim_{x\to1}\frac{(1+x)(x^{1/2}+x)}{x^{2/3}+x^{4/3}+x^2}=\frac{(1+1)(1+1)}{1+1+1}=\frac43$

3 0

3 years ago

The math department wants to sell pie slices to buy new math books. Each pie was cut into six slices. Two of the pies will be se

mars1129 [50]

We know that

Each pie was cut into six slices
there are a total of 48 pieces-----> divide by six to find the number of pies
48/6----> 8 pies

Two of the pies will be served to members of the department as courtesy
so
subtract 2 to the total of pies to find the pies available for sale
whole pies available for sale=8-2-----> 6 pies

the answer is
6 pies

7 0

3 years ago

Read 2 more answers

Find the volume of a cylinder with a height of 9 cm and a radius of 3 cm.

tangare [24]

12345678901234567890

6 0

2 years ago