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Katena32 [7]
3 years ago
10

What is the answer??

Mathematics
2 answers:
kupik [55]3 years ago
8 0

Yes you are correct .

Correct option is (B)

#$#HOPE YOU UNDERSTAND #$#

#$¥THANK YOU ¥$#

❤ ☺ ☺ ☺ ☺ ☺ ☺ ❤

liq [111]3 years ago
6 0

Answer:

the 4th one

I guess

if this is the wrong answer then let me know

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this algrebraic expression

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Solve the inequality.<br> 8-2x &lt; -x + 9
mezya [45]

Answer:

x > -1

Step-by-step explanation:

8-2x < -x+9\\8-2x-8 < -x+9-8\\-2x < -x+1\\-2x+x < -x+1+x\\-x < 1\\\left(-x\right)\left(-1\right) > 1\cdot \left(-1\right)\\x > -1

7 0
2 years ago
The sum of squares of two consecutive positive even integers is 52 more than their product. Find these numbers.
natulia [17]

Answer:

The first set of consecutive even integers equals (8 , 6)

The second set is ( - 8 and - 6) which also works.

Step-by-step explanation:

Equation

(x)^2 + (x + 2)^2 = (x)(x + 2) + 52            Remove the brackets on both sides

Solution

x^2 + x^2 + 4x + 4 = x^2 + 2x + 52        Collect the like terms on the left

2x^2+ 4x+ 4 = x^2 + 2x + 52                  Subtract right side from left

2x^2 - x^2 + 4x - 2x + 4 - 52  =  0          Collect the like terms

x^2 + 2x - 48 = 0                                     Factor

(x + 8)(x - 6) = 0

Answer

Try the one you know works.

x - 6 = 0

x = 6

Therefore the two integers are 6 and 8

6^2 + 8^2 = 100

6*8 + 52  = 100

So 6 and 8 is one set of  consecutive even numbers that works.    

========================

What about the other set.

x + 8 = 0

x = - 8

x and x + 2

- 8  and -8 + 2 = - 8, - 6

(- 8 )^2 + (- 6)^2 = 100

(-8)(-6) + 52 = 100

Both sets of consecutive numbers work.


5 0
3 years ago
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