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Paha777 [63]
3 years ago
7

Let Upper A equals left bracket Start 2 By 2 Matrix 1st Row 1st Column negative 2 2nd Column 4 2nd Row 1st Column 1 2nd Column 3

EndMatrix right bracketA=
−2 4
1 3
​, and Upper B equals left bracket Start 2 By 2 Matrix 1st Row 1st Column negative 2 2nd Column 1 2nd Row 1st Column 3 2nd Column 7 EndMatrix right bracketB=

−2 1
3 7
.a. Find

ABAB​,

if possible. b. Find

BABA​,

if possible.

c. Are the answers in parts a and b the ​same?

d. In​ general, for matrices A and B such that AB and BA both​ exist, does AB always equal​ BA?

a. Find

ABAB​,

if possible.
Mathematics
1 answer:
vagabundo [1.1K]3 years ago
7 0

Answer:

not

Step-by-step explanation:

\left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] *\left[\begin{array}{ccc}-2&1\\3&7\end{array}\right]=

First is A and Second is B

Let's find A*B

\left[\begin{array}{ccc}-2(-2)+4*3&-2*1+4*7\\1(-2)+3*3&1*1+3*7\end{array}\right] =\left[\begin{array}{ccc}16&26\\7&22\end{array}\right]

b)

\left[\begin{array}{ccc}-2&1\\3&7\end{array}\right]  \left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] =

Now let's find B*A

\left[\begin{array}{ccc}-2(-2)+1*1&-2*4+1*3\\3(-2)+7*1&3*4+7*3\end{array}\right] =\left[\begin{array}{ccc}5&-5\\1&23\end{array}\right]

c) They are not

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