I mol of anything is 6.02 * 10^23 (in this case molecules of water)
6 mols of water = x
1/6 = 6.02 * 10^23 / x Cross multiply
x = 6 * 6.02* 10^23
x = 3.612 * 10^24 molecules in 6 mols of water
Answer:
It is basically a way of telling you how to solve for different variables in the equation d=m/v
Explanation:
Answer:
The correct answer is 6.31 M
Explanation:
The molecular weight (MM) of NaOH is calculated as follows:
MM(NaOH) = Molar mass Na + Molar mass O + Molar mass H
= 23 g/mol + 16 g/mol + 1 g/mol
= 40 g/mol
We need the MM to convert from grams to moles. The molarity (moles of solute per liter of solution, in mol/L) can be calculated by dividing the mass into the volume in liters (195 ml = 0.195 L) and then multiplying by the MM as follows:
M = 49.24 g/0.195 L x 1 mol/40 g = 6.31 mol/L = 6.31 M
11.19%. This should be right. I have no doubt that you will get it right.
Answer:
Cd(s) + 1/2 O₂(g) ⇒ CdO(s) ΔH° = -258 kJ/mol
Explanation:
The standard heat of formation corresponds to the reaction of synthesis of 1 mole of the desired product from the simple substances in their most stable form under standard conditions (1 bar, 25°C). The resulting thermochemical equation is:
Cd(s) + 1/2 O₂(g) ⇒ CdO(s) ΔH° = -258 kJ/mol