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2 years ago

A ground test utilizing an auxiliary current electrode and an auxiliary potential electrode is known as the______.

Chemistry

1 answer:

kompoz [17]2 years ago

7 0

Answer:

The three-point test

Explanation:

The three-point test refers to a ground test utilizing an auxiliary current electrode and an auxiliary potential electrode.

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A 41.1 g sample of solid CO2 (dry ice) is added to a container at a temperature of 100 K with a volume of 3.4 L.A. If the contai

marta [7]

Answer:

Approximately 6.81 × 10⁵ Pa.

Assumption: carbon dioxide behaves like an ideal gas.

Explanation:

Look up the relative atomic mass of carbon and oxygen on a modern periodic table:

C: 12.011;
O: 15.999.

Calculate the molar mass of carbon dioxide $\rm CO_2$ :

$M\!\left(\mathrm{CO_2}\right) = 12.011 + 2\times 15.999 = 44.009\; \rm g \cdot mol^{-1}$ .

Find the number of moles of molecules in that $41.1\;\rm g$ sample of $\rm CO_2$ :

$n = \dfrac{m}{M} = \dfrac{41.1}{44.009} \approx 0.933900\; \rm mol$ .

If carbon dioxide behaves like an ideal gas, it should satisfy the ideal gas equation when it is inside a container:

$P \cdot V = n \cdot R \cdot T$ ,

where

$P$ is the pressure inside the container.
$V$ is the volume of the container.
$n$ is the number of moles of particles (molecules, or atoms in case of noble gases) in the gas.
$R$ is the ideal gas constant.
$T$ is the absolute temperature of the gas.

Rearrange the equation to find an expression for $P$ , the pressure inside the container.

$\displaystyle P = \frac{n \cdot R \cdot T}{V}$ .

Look up the ideal gas constant in the appropriate units.

$R = 8.314 \times 10^3\; \rm L \cdot Pa \cdot K^{-1} \cdot mol^{-1}$ .

Evaluate the expression for $P$ :

$\begin{aligned} P &=\rm \frac{0.933900\; mol \times 8.314 \times 10^3 \; L \cdot Pa \cdot K^{-1} \cdot mol^{-1} \times 298\; K}{3.4\; L} \cr &\approx \rm 6.81\times 10^5\; Pa \end{aligned}$ .

Apply dimensional analysis to verify the unit of pressure.

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4 years ago

7. Interpret Data A company plans to make an electronic device. They need to use an element that has chemical behavior similar t

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Germanium (Ge) is an element that has chemical behavior similar to that of silicon (Si) and lead (Pb). As it has an atomic mass greater than that of sulfur (S), but less than that of cadmium (Cd).

<h3>Why does the element of the same group have similar chemical behavior?</h3>

The chemical behavior of elements depends on the number of valence electrons in their outermost shell. Elements placed in the same group have the same number of valence electrons. Therefore, elements placed in the same group of the periodic table have similar chemical properties.

The elements having a similar outer electronic configuration in their atoms are arranged in the same group of the periodic table. These valence electrons are responsible chemical properties and reactivities of the elements.

Therefore, silicon and lead can be replaced by any element belonging to the same group in which Si and Pb are present. So we have germanium and tin. But germanium is the element that has an atomic mass greater than sulfur (S), but less than cadmium (Cd).

Learn more about elements with similar chemical behavior, here:

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