The sum of a number and 6 is 23 write an equation to represent this situation

1 answer:

5 0

The sum is the answer to an addition problem. Since we know the sum involves addition, we write an addition equation between the variable and the number given to us.
6 + n (number that was not given to use) = 23

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The product of two integers is about 50 less than one of the integers. Explain your answer. Think of three or more possible pair

Savatey [412]

An integer is a whole number and the product of numbers means to multiply them. So so we know that:
x * y = x - 50

So the product (x * y) is 50 less than one of the integers ( x - 50)

I can divide both sides by x:
y = (x - 50) / x where x is not zero
y = x/x - 50/x
y = 1 - 50/ x

x can no longer be zero since you cannot divide by zero

the only way for y to be a whole number is if 50/x is a whole number. 50/x can onky be a whole number if x is a factor of 50. so take any factor of 50 and that will be possible answers.
factors of 50: 1,2,5,10,25,50

these would be possible x values. To to find corresponding y values plug in x
y = 1 - 50/1
y = 1 - 50
y = -49
So first pair is (1, -49)
do the same for the rest and get
(2, -24)
(5, -9)
(10, -4)
(25, -1)
(50, 0)

7 0

3 years ago

Let omega be a complex number such that omega^3 = 1. Find all possible values of {1}{1 + \omega} + {1}{1 + \omega^2}. Enter all

Norma-Jean [14]

Answer:

1 is Answer.

Step-by-step explanation

$\frac{1}{1+omega^{2} } + \frac{1}{1+omega }\\$