Triangle JKL has vertices J(−2, 2) , K(−3, −4) , and L(1, −2) .
Rule: (x, y)→(x + 8, y + 1 )
J’ (-2, 2) → (-2 + 8, 2 + 1 ) → (6, 3 )
K’ (-3, -4) → (-3 + 8, -4 + 1 ) → (5, -3 )
L’ (1, -2) → (1 + 8, -2 + 1 ) → (9, -1)
J’ (6,3)
K’ (5,-3)
L’ (9,-1)
Hope this helps!
For the first one the answer is y=-1x+6 which means x=-1 and y=6
[tex]Domain:x\geq0\\\\\sqrt{x}\leq5\ \ \ \ |square\ both\ sides\\\\x\leq25[tex]
Answer: B. 0 ≤ x ≤ 25
Answer:
A, B, & D
Step-by-step explanation:
Jaime is at the smallest angle from the two friends.
Pat is at an angle of 90° to Chris and Jaime.
If they meet at Pat’s entrance, then Chris will have walked a shorter distance than Jaime.
Vertex = (6, 5)
axis of symmetry is line x = 6
A third point in the parabola is (12, 0)
equation using the vertex is y = -a(x - 6)^2 + 5 = -a(x^2 - 12x + 36) + 5 = -ax^2 + 12ax - 36a + 5
since the parabola passes through point (0, 0)
i.e. -36a + 5 = 0
a = 5/36 = 0.139
Therefore, the equation is y = -0.139x^2 + 12(0.139)x = -0.139x^2 + 1.667x
