3 years ago

If the scale is 1 in to 3 ft, and the scale drawing shows a length of 4 inches, what is the length of the real world figure

Mathematics

1 answer:

Orlov [11]3 years ago

5 0

Answer:

Step-by-step explanation:

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Evaluate. 10 • (-4) Enter your answer in the box.

wolverine [178]

Answer:

it is -40

Step-by-step explanation:

yes yes right????

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3 years ago

Read 2 more answers

a park is 4 times as long as it is wide. if the distance around the park is 12.5 kilometers, what is the area of the park

Rom4ik [11]

X -length
y wide

x=4y
2x+2y=12,5

x=4y
8y+2y=12,5

x=4y
y=1,25

x=5
y=1,25

area
x*y=5*1,25=6,25

3 0

3 years ago

Use the following function rule to find f(2). f(x) = 10x f(2)=

zalisa [80]

It would be 20, since you’re replacing the x value with 2. 10(2) is 20.

3 0

1 year ago

Find the value of x, y, and z in the figure below: ہ 2y IN 2x 90° t

natima [27]

Answer:

x=30°

y=15°

z=150°

Step-by-step explanation:

2x+90+x=180°

2x=180°-90°

x=90/3

x=30

2y=x

y= 30/2

y=15°

2y°+z°=180°

2(15°)+z°=180°

z=180°-30°

z=150°

Hope it helps! :)

6 0

2 years ago

Solve the triangle. Round your answers to the nearest tenth.

wel

Answer:

m∠A ≈ 43°

m∠B ≈ 55°

mBC ≈ 20

Step-by-step explanation:

Law of Sines: $\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}$

Step 1: Find m∠B

$\frac{29}{sin82} =\frac{24}{sinB}$

Step 2: Solve for ∠B

29sinB = 24sin82°

sinB = 24sin82°/29

B = sin⁻¹(24sin82°/29)

B = 55.038°

Step 3: Find m∠A

180 - (55.038 + 82)

180 - 137.038

m∠A = 42.962°

Step 4: Find BC

$\frac{29}{sin82} =\frac{BC}{sin42.962}$

Step 5: Solve for BC

29sin42.962° = BCsin82°

BC = 29sin42.962°/sin82°

BC = 19.9581

4 0

3 years ago