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azamat
2 years ago
15

Solve pls brainliest

Mathematics
2 answers:
worty [1.4K]2 years ago
8 0

Answer:

x = 6.4

Step-by-step explanation:

Step 1: Divide both sides by 4.

  • \frac{4x}{4}=\frac{25.6}{4}
  • x = 6.4

Step 2: Check if solution is correct.

  • 4(6.4)=25.6
  • 25.6=25.6

Therefore, x = 6.4.

Gnoma [55]2 years ago
7 0

Answer:

4x = 25.6

4x = 256 / 10

x = 256 / (10×4)

x = 64 / 10 (256 ÷ 4 = 64)

x = 6.4

so, answer is 6.4 .

Step-by-step explanation:

brainliest plz

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Answer:

<h2>1267 456 578 123 679 333 5</h2>

Step-by-step explanation:

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7 0
3 years ago
Find the value of x.<br> When a leg is 6<br> units and the<br> hypotenuse is 12<br> units.
DIA [1.3K]

Answer:

6√3

Step-by-step explanation:

6^2+x^2=12^2

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3 0
3 years ago
A helicopter is flying above a town. the local high school is directly to the east of the helicopter at a 20° angle of depressio
guapka [62]
Answer: 4.5 miles

Explanation:

When you draw the situation you find two triangles.

1) Triangle to the east of the helicopter

a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°

b) hypotensue = distance between the high school and the helicopter

c) opposite-leg to angle 20° = heigth of the helicopter

d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x

2) triangle to the west of the helicopter

a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°

b)  distance between the helicopter and the elementary school = hypotenuse

c) opposite-leg to angle 62° = height of the helicopter

d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x

3) tangent ratios

a) triangle with the helicpoter and the high school

tan 20° = Height / x ⇒ height = x tan 20°

b) triangle with the helicopter and the elementary school

tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°

c) equal the height from both triangles:

x tan 20° = (5 - x) tan 62°

x tan 20° = 5 tan 62° - x tan 62°

x tan 20° + x tan 62° = 5 tan 62°

x  (tan 20° + tan 62°) = 5 tan 62°

⇒ x = 5 tant 62° / ( tan 20° + tan 62°)

⇒ x = 4,19 miles

=> height = x tan 20° = 4,19 tan 20° = 1,525 miles

4) Calculate the hypotenuse of this triangle:

hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²

hipotenuse = 4.46 miles

Rounded to the nearest tenth = 4.5 miles

That is the distance between the helicopter and the high school.
5 0
3 years ago
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A right rectangular prism is 534 cm wide, 1012 cm long, and 8 cm tall. What is the volume of the prism?
Maru [420]
4.32×10^6 will be ur answer I believe or 1012 * 534 * 8 = 4323264
3 0
3 years ago
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20 - k/15 = 17 What is k?
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20 - k/15 = 17
20 - 17 = k/15
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