All categories

3 years ago

Ugh idkplease help ASAP

Mathematics

1 answer:

Travka [436]3 years ago

7 0

12/23 = 0.5217 = 52%

You might be interested in

If the total labor cost is $865,000 and 12 percent is for concession staff, how much of the labor cost is for concession staff?

stepladder [879]

12% of $865,000 is $103,800

4 0

3 years ago

If tan(A+B)=8 and tan B = 1/57 find tan A <br> Plz show work

Degger [83]

Answer:A=8-1/57=455/57=7.98

Step-by-step explanation:

8 0

3 years ago

Any help? Will mark as brainlest!

Effectus [21]

Answer:

24/4/-a+12=/9d

Step-by-step explanation:

7 0

2 years ago

6 wrestlers compete in a competition. if each wrestler wrestles one match with each other wrestler, what are the total numbers o

PolarNik [594]

The total number of wrestlers are 6 and each have to wrestle each other wrestler only once.

It means, the first wrestler have 5 opponent, second have 4 opponents , third have three oponenets , fourth have two opponents and the fifth have only one opponent.

So the total number of matches = 5+4+3+2+1 =15

3 0

3 years ago

Read 2 more answers

I need help if you can that would be great thank you

liq [111]

Answer:

Simplifying the expression $(3\:.\:2)^5\div (3^2\:.\:2^3)$ so, there is only one power of each base we get $\mathbf{3^3\:.\:2^2}$

Option D is correct answer.

Step-by-step explanation:

We need to simply the expression $(3\:.\:2)^5\div (3^2\:.\:2^3)$ so, there is only one power of each base.

Solving:

$(3\:.\:2)^5\div (3^2\:.\:2^3)$

We can write it as:

$\frac{(3\:.\:2)^5}{3^2.2^3}$

Now using exponent rule: $(a\:.\:b)^m=a^m\:.\:b^n$

$\frac{3^5\:.\:2^5}{3^2.2^3}$

Now using the exponent rule: $\frac{a^m}{a^n}=a^{m-n}$ the bases should be same

$3^{5-2}\:.\:2^{5-3}\\=3^3\:.\:2^2$

So, simplifying the expression $(3\:.\:2)^5\div (3^2\:.\:2^3)$ so, there is only one power of each base we get $\mathbf{3^3\:.\:2^2}$

Option D is correct answer.

5 0

2 years ago