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sasho [114]
3 years ago
8

What is the simplified expression for 3 power 3 multiplied by 3 power 3 over 3 power 4

Mathematics
2 answers:
dimaraw [331]3 years ago
7 0
(3^3 * 3^3) / 3^4

multiplying powers with the same base, keep the base and add the powers

(3^(3 + 3)) / 3^4 =
3^6 / 3^4

dividing powers with the same base, keep the base and subtract the powers

3^6/3^4 = 3^(6-4) = 3^2

simplified expression is 3^2 or 9
Arlecino [84]3 years ago
5 0

The simplified expression for \frac{3^3 * 3^3}{3^4} is:

3^2 / Three to the Second Power.

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3 years ago
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I need the correct answer
Nikolay [14]

Answer:

1) 27/2 2) 8pi 3) 48 4) 16+2pi

Step-by-step explanation:

1) The length of the triangle is 9 (found by finding the distance between (-5,-3) and (4,-3)) and the height is 3 (found by finding the distance between (1,0) and (1,-3)). The area of a triangle is 1/2 (length times height) which in this case is 27/2.

2) The shape is a semicircle, so the area is 1/2 pi*r^2.

1/2 * pi * r^2=8pi

3) B*H=8*6=48

4) The figure is a semicircle and a square.

The area of the semicircle is 1/2 * pi * r^2=2pi

The area of the square is b*h=4*4=16

The area is 16+2pi.

5 0
2 years ago
Is 0.2971 irrational?
Vladimir [108]

Answer:

Yes

Step-by-step explanation:

An irrational number can be written as a decimal, but not as a fraction. An irrational number has endless non-repeating digits to the right of the decimal point.

7 0
3 years ago
Use a graphing calculator to solve the equation -2sin(theta)= 1.2 in the interval from 0 to 2pi.
elena-s [515]

Answer:

\theta=\pi +arcsin(\frac{3}{5})\approx 3.785\\\\\theta=2\pi -arcsin(\frac{3}{5} ) \approx 5.64  

Step-by-step explanation:

As you can see from the graph I attached you, the possible solutions in the interval from 0 to 2π are approximately:

\theta=3.7\\\\and\\\\\theta=5.7

So, it's useful to solve the equation too, in order to verify the result:

-2sin(\theta)=1.2\\\\sin(\theta)=-\frac{3}{5}

Taking the inverse sine of both sides:

\theta=\pi +arcsin(\frac{3}{5})\approx 3.785\\\\\theta=2\pi -arcsin(\frac{3}{5} ) \approx 5.64

Using this result we can conclude the solutions in the interval from 0 to 2π are approximately:

\theta\approx 3.785\\\\\theta \approx 5.64

8 0
3 years ago
A cereal company is exploring new cylinder-shaped containers. Two possible containers are shown in the diagram.x is 6 and r=4.5
KatRina [158]

Answer:

Container \rm X will have less label area than container \rm Y by about 9\; \rm in.

Step-by-step explanation:

A rectangular sheet of paper can be rolled into a cylinder. Conversely, the lateral surface of a cylinder can be unrolled into a rectangle- without changing the area of that surface.

Indeed, the width of that rectangle will be the same as the height of the cylinder. On the other hand, the length of that rectangle should be exactly equal to the circumference of the circles on the top and the bottom of the cylinder. In other words, if a cylinder has a height of h and a radius of r at the top and the bottom, then its lateral surface can be unrolled into a rectangle of width h and length 2\,\pi\, r.

Apply this reasoning to both cylinder \mathrm{X} and \rm Y:

For cylinder \mathrm{X}, h = 6\; \rm in while r = 4.5\; \rm in. Therefore, when the lateral side of this cylinder is unrolled:

  • The width of the rectangle will be 6\; \rm in, while
  • The length of the rectangle will be 2 \, \pi \times 4.5\; \rm in = 9\, \pi\; \rm in.

That corresponds to a lateral surface area of 54\, \pi\; \rm in^2.

For cylinder \rm Y, h = 10.5\; \rm in while r = 3\; \rm in. Similarly, when the lateral side of this cylinder is unrolled:

  • The width of the rectangle will be 10.5\; \rm in, while
  • The length of the rectangle will be 2\pi\times 3\; \rm in = 6\,\pi \; \rm in.

That corresponds to a lateral surface area of 63\,\pi \; \rm in^2.

Therefore, the lateral surface area of cylinder \rm X is smaller than that of cylinder \rm Y by 9\,\pi\; \rm in^2.

5 0
3 years ago
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