Answer:
1) 27/2 2) 8pi 3) 48 4) 16+2pi
Step-by-step explanation:
1) The length of the triangle is 9 (found by finding the distance between (-5,-3) and (4,-3)) and the height is 3 (found by finding the distance between (1,0) and (1,-3)). The area of a triangle is 1/2 (length times height) which in this case is 27/2.
2) The shape is a semicircle, so the area is 1/2 pi*r^2.
1/2 * pi * r^2=8pi
3) B*H=8*6=48
4) The figure is a semicircle and a square.
The area of the semicircle is 1/2 * pi * r^2=2pi
The area of the square is b*h=4*4=16
The area is 16+2pi.
Answer:
Yes
Step-by-step explanation:
An irrational number can be written as a decimal, but not as a fraction. An irrational number has endless non-repeating digits to the right of the decimal point.
Answer:
Step-by-step explanation:
As you can see from the graph I attached you, the possible solutions in the interval from 0 to 2π are approximately:

So, it's useful to solve the equation too, in order to verify the result:

Taking the inverse sine of both sides:

Using this result we can conclude the solutions in the interval from 0 to 2π are approximately:

Answer:
Container
will have less label area than container
by about
.
Step-by-step explanation:
A rectangular sheet of paper can be rolled into a cylinder. Conversely, the lateral surface of a cylinder can be unrolled into a rectangle- without changing the area of that surface.
Indeed, the width of that rectangle will be the same as the height of the cylinder. On the other hand, the length of that rectangle should be exactly equal to the circumference of the circles on the top and the bottom of the cylinder. In other words, if a cylinder has a height of
and a radius of
at the top and the bottom, then its lateral surface can be unrolled into a rectangle of width
and length
.
Apply this reasoning to both cylinder
and
:
For cylinder
,
while
. Therefore, when the lateral side of this cylinder is unrolled:
- The width of the rectangle will be
, while - The length of the rectangle will be
.
That corresponds to a lateral surface area of
.
For cylinder
,
while
. Similarly, when the lateral side of this cylinder is unrolled:
- The width of the rectangle will be
, while - The length of the rectangle will be
.
That corresponds to a lateral surface area of
.
Therefore, the lateral surface area of cylinder
is smaller than that of cylinder
by
.