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kirill115 [55]
3 years ago
10

What happens if you overheat copper sulfate

Chemistry
1 answer:
Sergio039 [100]3 years ago
8 0
If  you  overheat  copper  sulfate  higher  of   mass  will  be  lost that  is  copper  sulfate  will  loss  sulfur  and  oxygen which  led to a  higher loss  of  mass than  if  you  would   have heated enough. This  higher  mass lost will  be shown  in  calculation  as  percentage of  water  lost
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What is the term for a solid that forms when two solutions are mixed?
Inessa [10]

Option D

A precipitate is the term for a solid that forms when two solutions are mixed

<u>Explanation:</u>

A solid set from a couple of solutions is termed a precipitate. A precipitate is an unsolved solid that makes when a pair of solutions are fused and react chemically. Unsolvable means that the solid will not melt.  When the effect transpires in a liquid solution, the solid developed is denominated the 'precipitate'.

The substance that generates the solid to make is termed the 'precipitant'. Seldom the development of a precipitate symbolizes the existence of a chemical reaction. Precipitation may additionally transpire immediately from a supersaturated solution.

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3 years ago
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Using the word bank explain why increasing the temperature increases the rate of reaction​
katrin2010 [14]

Answer:Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.

Explanation:

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3 years ago
If 25.4 grams of water react to form 2.8 grams of hydrogen, how many grams of oxygen must simultaneously be formed?
aalyn [17]
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If 4.65 LL of CO2CO2 gas at 22 ∘C∘C at 793 mmHg mmHg is used, what is the final volume, in liters, of the gas at 35 ∘C∘C and a p
otez555 [7]

Answer:

About 7.9 L.

Explanation:

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\displaystyle PV = nRT

Because the amount of carbon dioxide does not change, we can rearrange to formula to:
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Because the right-hand side stays constant, we have that:
\displaystyle \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} = nR

Hence substitute initial values and known final values:
\displaystyle \begin{aligned} \frac{(793\text{ mm Hg})(4.65 \text{ L})}{(22 \text{ $^\circ$C})} & = \frac{(743 \text{ mm Hg})V_2}{(35\text{ $^\circ$C})} \\ \\ V_2 & = 7.9\text{ L}\end{aligned}

Therefore, the final volume is about 7.9 L.

8 0
2 years ago
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{K}^{42} \: ---> {Ca}^{40} + {2e}^{0}

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