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Lina20 [59]
3 years ago
14

The

Chemistry
1 answer:
myrzilka [38]3 years ago
3 0
I’m pretty sure the answer is a. greater

hope this helps!!
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How to Calculate the de Broglie wavelength for each of the following ? a. an electron with a velocity 10.% of the speed of light
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H = planks constant 
<span>m = mass of the object </span>
<span>u = velocity of the object </span>

<span>h = 6.626 * 10^-34 J/s </span>
<span>the mass of an electron is 9.12*10^-31 kg </span>
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3 years ago
Practice Problem: True Stress and Strain A cylindrical specimen of a metal alloy 49.7 mm long and 9.72 mm in diameter is stresse
amm1812

Answer:

The true stress required = 379 MPa

Explanation:

True Stress is the ratio of the internal resistive force to the instantaneous cross-sectional area of the specimen. True Strain is the natural log to the extended length after which load applied to the original length. The cold working stress – strain curve relation is as follows,

σ(t) = K (ε(t))ⁿ, σ(t) is the true stress, ε(t) is the true strain, K is the strength coefficient and n is the strain hardening exponent

True strain is given  by

Epsilon t =㏑ (l/l₀)

Substitute㏑(l/l₀) for ε(t)

σ(t) = K(㏑(l/l₀))ⁿ

Given values l₀ = 49.7mm, l =51.7mm , n =0.2 , σ(t) =379Mpa

379 x 10⁶ = K (㏑(51.7/49.7))^0.2

K = 379 x 10⁶/(㏑(51.7/49.7))^0.2

K = 723.48 MPa

Knowing the constant value would be same as the same material is being used in the second test, we can find out the true stress using the above formula replacing the value of the constant.

σ(t) = K(㏑(l/l₀))ⁿ

l₀ = 49.7mm, l = 51.7mm, n = 0.2, K = 723.48Mpa

σ(t) = 723.48 x 106 x (㏑(51.7/49.7))^0.2

σ(t) = 379 MPa

The true stress necessary to plastically elongate the specimen is 379 MPa.

6 0
3 years ago
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With the aid of a balanced chemical equation explain Chemical Reactions and the Types Of Chemical Reaction
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Answer:

Answers

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5.)2NaClO 3 → 2NaCl + 3O 2

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Explanation:

''.''

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3 years ago
True or False. Will give brainliest if correct!
Jet001 [13]

i think its is true

(............)

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