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Hey there, Dudedan!
In a#b = a+2b, we have the first term, a, plus 2 times the second term, b.
Let's try that with 3#4.
3#4 = 3+2(4) =
3 + 8 = 11.
Hope this helps!
Answer:
|x + 5|= 7
-7<(x+5)<7
-7<x+5<7
-7-5<x+5-5<7-5
-12 < x <2
Step-by-step explanation:
The answer to this question would be x=a2y2