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Veronika [31]
3 years ago
11

Katie divided 4.25 by 0.25 and got a quotient of 0.17 what is wrong?

Mathematics
2 answers:
nalin [4]3 years ago
8 0
It should be 17 because 4.25 divided by 0.25 is the same as 425/25 which is 17.
Anna71 [15]3 years ago
5 0
She put the decimal place in the wrong spot. its 17

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DU
Grace [21]

Answer:

a    true

b   false

c.    false

d.   true

e.    false

f.   true

Step-by-step explanation:

The function is y =35+8x where x is the number of items sold and y is the earnings

To determine if the point is on the graph substitute the point in and see if it is true

a (7,91)

91 = 35+ 8(7)

91 = 35+ 56  

91 = 91   true

b(11, 121)

121 = 35+ 8(11)

121 = 35+ 88  

121 = 123   false

c. (9, 110)

110 = 35+ 8(9)

110 = 35+ 72  

110 = 107   false

d. (4,67)

67 = 35+ 8(4)

67 = 35+ 32  

67 = 67   true

e. (5,72)

72 = 35+ 8(5)

72 = 35+ 40  

72 = 75   false

f. (3, 59)

59 = 35+ 8(3)

59 = 35+ 24  

59 = 59   true

8 0
3 years ago
4. Kay and Allen sell cell phones. Last month Kay sold 17 more cell phones than Allen. Together they both sold 117 cell phones.
forsale [732]

Answer:

Allen sold 50 cell phones while Kay sold 67 cell phones.

Step-by-step explanation:

Let the number of cell phones sold by Allen be x. This will imply that the number of cell phones sold by Kay is x + 17.

Furthermore, we are informed that together they sold a total of 117 cell phones. Therefore, we use the following equation to determine the number of cell phones sold by each;

x + x + 17 = 117

2x + 17 = 117

2x = 100

x = 50

Therefore, Allen sold 50 cell phones while Kay sold 67 cell phones.

7 0
3 years ago
Read 2 more answers
What is the GCF of 18 and 130?<br> 2,<br> 3,<br> 5,<br> 8,<br> 13,
grandymaker [24]
2 because the others aren’t factors of both
6 0
2 years ago
Read 2 more answers
PLEASE HELP ASAP!!!!!!!
umka2103 [35]

Answer:

dum there is part A prat B and C

Step-by-step explanation:

5 0
3 years ago
Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f
castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean (\mu) = 115 \times 20

= 2300

Standard deviation = 20 \times \sqrt{115}

Standard deviation (SD) = 214.4761

TO find:

a) P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})

P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})

P(x > 3500)= P(Z > \dfrac{1200}{214.4761})

P(x > 3500)= P(Z >5.595)

From the Z-table, since 5.595 is > 3.999

P(x > 3500)=1-0.9999

P(x > 3500) = 0.0001

b)

Here, the replacement time for the mean (\mu) = \dfrac{0+0.5}{2}

= 0.25

Replacement time for the Standard deviation \sigma = \dfrac{0.5-0}{\sqrt{12}}

\sigma = 0.1443

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = \sqrt{(115\times 20^2) +(114\times (0.1443)^2)}

= \sqrt{(115\times 400) +(114\times 0.02082249}

= \sqrt{(46000) +2.37376386}

= \sqrt{(46000) +(2.37376386)}

= \sqrt{46002.374}

= 214.482

Now; the required probability:

P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})

P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})

P(x > 4125) = P(Z >8.376)

P(x > 4125) =1-  P(Z

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0
2 years ago
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