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Rudik [331]
3 years ago
14

In a bag of candy hearts the ratio of pink to green hearts is 3 to 5. If there are 35 green hearts, how many pink hearts are in

the bag?
Mathematics
1 answer:
elixir [45]3 years ago
4 0

Answer:

there are 21 pink hearts

Step-by-step explanation:

hope this helps

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A game has a circular playing area in which you must hit a ball into a circular hole. The area of the playing area is 16ft2. The
frez [133]

Considering the area of the hole, it is found that there is a 4.9% probability of hitting a ball into the circular hole.

<h3>What is the area of a circle?</h3>

The area of a circle of radius r is given by:

A = \pi r^2

In this problem, the hole has a diameter of 1 ft, hence it is radius is of r = 1 ft/2 = 0.5 ft, and it's area is given by:

A = \pi \times (0.5)^2 = 0.7854 \text{ft}^2

Hence the probability is given by:

p = 0.7854/16 = 0.049 = 4.9%

More can be learned about probabilities at brainly.com/question/14398287

#SPJ1

5 0
2 years ago
Does 23^-1 (mod 1000) exist? If yes solve it.
sweet [91]

Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).

Let <em>x</em> be the inverse. Then <em>x</em> is such that

23<em>x</em> ≡ 1 (mod 1000)

Use the Euclidean algorithm to solve for <em>x</em> :

1000 = 43×23 + 11

23 = 2×11 + 1

→   1 ≡ 23 - 2×11   (mod 1000)

→   1 ≡ 23 - 2×(1000 - 43×23)   (mod 1000)

→   1 ≡ 23 - 2×1000 + 86×23   (mod 1000)

→   1 ≡ 87×23 - 2×1000 ≡ 87×23   (mod 1000)

→   23⁻¹ ≡ 87   (mod 1000)

3 0
3 years ago
In the image it appears everything
rosijanka [135]
X = -3 it's practically the y intercept in which x is equals 0
4 0
3 years ago
Read 2 more answers
Find x and y plz help :(
liraira [26]

Answer:

D. x = 5.4, y = 6.67

Step-by-step explanation:

The triangles are similar as per problem description, so the ratios match:

y/5 = 4/3

x/3 = 9/5

let's solve:

y/5 = 4/3

3y/5 = 4

3y = 20

y = 6.(6)

x/3 = 9/5

5x/3 = 9

5x = 27

x = 5.4

5 0
3 years ago
Read 2 more answers
what is the polynomial function of lowest degree with leading coefficient of 1 and roots 2 and 1 + square root2
Marta_Voda [28]
If the roots to such a polynomial are 2 and 1+\sqrt2, then we can write it as

(x-2)(x-(1+\sqrt2))

courtesy of the fundamental theorem of algebra. Now expanding yields

(x-2)(x-1-\sqrt2)=x^2-2x-(1+\sqrt2)x+2(1+\sqrt2)=x^2-(3+\sqrt2)x+2+2\sqrt2

which would be the correct answer, but clearly this option is not listed. Which is silly, because none of the offered solutions are *the* polynomial of lowest degree and leading coefficient 1.

So this makes me think you're expected to increase the multiplicity of one of the given roots, or you're expected to pull another root out of thin air. Judging by the choices, I think it's the latter, and that you're somehow supposed to know to use 1-\sqrt2 as a root. In this case, that would make our polynomial

(x-2)(x-(1+\sqrt2))(x-(1-\sqrt2))=x^3-4x^2+3x+2

so that the answer is (probably) the third choice.

Whoever originally wrote this question should reevaluate their word choice...
5 0
3 years ago
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