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Gwar [14]
3 years ago
15

What is the solution of the equation 3x – 1 = 7? Round your answer to the nearest ten-thousandth

Mathematics
1 answer:
tiny-mole [99]3 years ago
3 0

Answer:

x = 2.6667 (rounded)

Step-by-step explanation:

Move the constant to the right side and change its sign.

3x = 7 + 1.

Add the numbers.

3x = 8.

Divide both sides by 3.

x = 8/3 = 2.6667 (Rounded to the nearest ten-thousandth).

Hope this helps.

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How do you work this problem out <br> Y+1/2=7/10
ch4aika [34]
Y= 1/5, this is because 1/2 is 5/10 and 1/5 is 2/10, therefore 5/10 + 2/10= 7/10
4 0
4 years ago
Solve y = -25x + 600
olga nikolaevna [1]

Answer:

-\frac{y}{25} +24

Step-by-step explanation:

.

5 0
3 years ago
the length of a soccer pitch is 20 m less than twice its width. the area of the pitch is 6000m^2. find its dimensions.
Setler79 [48]
X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:

x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60

x=60
2x-20=2(60)-20=120-20=100

Solution: the length is 100 m, and the width is 60 m.

To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.


8 0
3 years ago
Question 15 A party rental company has chairs and tables for rent. The total cost to rent 8 chairs and 3 tables is $38 . The tot
SIZIF [17.4K]

Answer:

Each table is $6 and each chair is $2.50

Step-by-step explanation:

6 0
3 years ago
An object is launched from the ground. The object’s height, in feet, can be described by the quadratic function h(t) = 80t – 16t
White raven [17]

Answer:

The object hits the ground 5 seconds after being launched.

Step-by-step explanation:

The height of the object in t seconds after being launched is given by the following equation:

h(t) = 80t - 16t^{2}

When will the object hit the ground after it is launched?

This is t for which h(t) = 0.

So

80t - 16t^{2} = 0

16t(5 - t) = 0

Then

16t = 0

t = 0

This is the launch point

5 - t = 0

t = 5

So

The object hits the ground 5 seconds after being launched.

5 0
4 years ago
Read 2 more answers
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