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3 years ago

Are any concentric circles shown? yes no

Mathematics

2 answers:

dimulka [17.4K]3 years ago

5 0

No because there is no picture and circles

Debora [2.8K]3 years ago

5 0

I think that the answer is still No.

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Nine times the sum of a number and eleven is -108. What is the number?

katovenus [111]

Answer:

So like I shouldn't represent with a letter? I should use 2?

8 0

3 years ago

Which is the correct first line for dividing the function

Firlakuza [10]

Given function is f(x) = x³ -12x +16.

We can write it as x³ +0x² -12x +16.

We need to write the numbers in order from left to right, so it would be {1, 0, -12, 16}.

Given factor is x -2 = 0, that means x = 2. So we need to divide the numbers by 2.

So correct way to divide the function would be 2 L 1, 0, -12, 16.

Hence, option C is correct.

6 0

3 years ago

Read 2 more answers

21 first-graders and 54 other students attended a school assembly. What percentage of the students at the assembly were first-gr

Degger [83]

21+ 54= 76

21/76= 27.6%

5 0

3 years ago

Prove that the triangle EDF is isosceles. Give reasons for your answer.

Gekata [30.6K]

Answer:

$\triangle EDF$ is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are given the following things:

$\angle EDF = y$

$\text{External }\angle DFG = 90 +\dfrac{y}{2}$

Let us try to find out $\angle E$ and $\angle DFE$ . After that we will compare them.

Finding  $\angle DFE$ :

Side EG is a straight line so $\angle GFE = 180$

$\angle GFE$ is sum of internal $\angle DFE$ and external $\angle DFG$

$\angle GFE = 180 = \angle DFE + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)$

Finding  $\angle E$ :

Property of external angle: External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external $\angle DFG$ = $\angle E + \angle EDF$

$\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2} -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)$

Comparing equations (1) and (2):

It can be clearly seen that:

$\angle DFE = \angle E =90-\dfrac{y}{2}$

The two angles of $\triangle EDF$ are equal hence $\triangle EDF$ is isosceles.

8 0

3 years ago

5. Luis found a new text messaging plan which will charge him $2.00 for 80 messages. Using this

Pavel [41]

I think that Luis would have to pay $22.50

7 0

3 years ago