1) from smaller to higher:
1,5,11,11,17
2) find the mean
<span>1 + 5 + 11 + 11 + 17 = </span><span>45
</span>mean = 45/5 = 9
Variance = Σ(x- mean)²/(N-1)
[(1-9)² + (5-9)²+(11-9)² + (11-9)²+ (17-9)² ]'(5-1) = 38
Variance = 38
Answer:
I belive the answer would be 4ajjdbnmsfnksfnbdnsdbcs,mdv bn,zdb xzvndzsmbznx,vsdanvbf. : ) ahaha
The coordintates of the point mark the opposite-leg and adjacent leg of a right triangle.
The opposed-leg is the y-coordinate, this is 3.
The adjacent-leg is the x-coordinate, this is 4.
The tangent of the angle q is given by:
tan(q) = y-coordinate / x-coordinate = 3 / 4 = 0.75
Answer: 0.75
Complete question :
A data set includes data from student evaluations of courses. The summary statistics are nequals92, x overbarequals4.09, sequals0.55. Use a 0.10 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
Answer:
H0 : μ = 4.25
H1 : μ < 4.25
T = - 2.79
Pvalue =0.0026354
we conclude that there is enough evidence to conclude that population mean is different from 4.25 at 10%
Step-by-step explanation:
Given :
n = 92, xbar = 4.09, s = 0.55 ; μ = 4.25
H0 : μ = 4.25
H1 : μ < 4.25
The test statistic :
T = (xbar - μ) ÷ s / √n
T = (4.09 - 4.25) ÷ 0.55/√92
T = - 0.16 / 0.0573414
T = - 2.79
The Pvalue can be obtained from the test statistic, using the Pvalue calculator
Pvalue : (Z < - 2.79) = 0.0026354
Pvalue < α ; Hence, we reject the Null
Thus, we conclude that there is enough evidence to conclude that population mean is different from 4.25 at 10%
Answer:
66.67%
Step-by-step explanation:
75 /100 = .75
.75n = 45
45/.75 = 60
60 is n
60/90 = .666667
.666667 * 100 = 66.67%
