We need to know the density of Marble City, hence we know the density of Pebble City.
MC density = population/area
MC density = 52,348/125
MC density = 418.784 people/miles
From the question, we know that the two cities have the same population density.
PC density = MC density
PC density = 418.784 people/miles
Use the density formula to figure out the dimension of PC
PC density = population/area
418.784 = 85,312/(l × w)
(l × w) = 85,312/418.784
11.8 w = 85,312/418.784
11.8 w = 203.7
w = 203.7/11.8
w = 17.2
The closest value of x is 17 miles
For congruency the related sides need to be similar, which means they letters need to be in the correct order.
AB would be EF, BC would be FG and AC would be EG
This would make the correct answer BC ≅ FG
Answer:
6/10
And 9/15
Step-by-step explanation:
Answer:
The 95% confidence interval would be given by (0.0772;0.1308)
Step-by-step explanation:
For this case we can calculate the estimated proportion like this:

We can assume that the normal model can be used since we satisfy two conditions:


The confidence level for this case is 95% of confidence, and the significance is given by
and
. And the critical value would be given by:
The confidence interval for the mean is given by the following formula:
Replacing the values we got:
The 95% confidence interval would be given by (0.0772;0.1308)