Find the intersection point between the 2 restraint equations:

Substitute back in to find y-value:

P is maximized at point (12,6)
It would be sometimes because it can be 82.2% but if you round it the closest one would be 80% if it was 84.7% its closer to 85 so it would be 85% I hope I helped you out rate the answer if I got it right thanks!
Answer:
2630 g
Step-by-step explanation:
From the given information:
Given that:
mean (μ) = 3750 g
Standard deviation (σ) = 500
Suppose the hospital officials demand special treatment with a percentage of lightest 3% (0.03) for newborn babies;
Then, the weight of birth that differentiates the babies that needed special treatment from those that do not can be computed as follows;
P(Z < z₁) = 0.03
Using the Excel Formula; =NORMSINV(0.03) = -1.88
z₁ = - 1.88
Using the test statistics z₁ formula:


By cross multiply, we have:
-1.88 × 500 = X - 3570
-940 = X - 3570
-X = -3570 + 940
-X = -2630
X = 2630 g
Hence, 2630 g is the required weight of birth that differentiates the babies that needed special treatment from those that do not
10.8/12 x 100 = 90%
So he saves 10%
Add the expensive ones that equals 10.80 and then add all them together which gives you £12 you put 10.80 over 12 and multiply by 100 to find the percentage you have and then minus that from 100 which will give you your answer of 10%
"The sum of a number and 7"
Sum implies addition.
We would write this part as <em>n + 7</em>.
Then we would write the "9 times" part in like this:
<em>9 </em><em>·</em><em> </em><em>(n + 7)</em><em>
</em>We can't write just 9 · n + 7 without the parentheses, because then we would be multiplying just 9 and n instead of 9 and the sum of n and 7. (order of operations says we must do multiplication first)