1) I put them in two separate brakets.
2) I solved it by equating both of them.
Answer: B: (y + z = 6) × -5
Step-by-step explanation:
if you multiply 'y' by -5 it turns into -5y. Therefore when you add -5y and 5y together, you get 0y which is what you want when eliminating the y-term.
Y and the angle marked 60 degrees are internal alternate angles and are equal
so y = 60
Answer:
The best estimate of the number of times out of 39 that Ariana is on time to class is 27.
Step-by-step explanation:
For each class, there are only two possible outcomes. Either Ariana is on time, or she is not. The probability of Ariana being on time for a class is independent of other classes. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:

The probability that Ariana is on time for a given class is 69 percent.
This means that 
If there are 39 classes during the semester, what is the best estimate of the number of times out of 39 that Ariana is on time to class
This is E(X) when n = 39. So

Rounding
The best estimate of the number of times out of 39 that Ariana is on time to class is 27.
Answer:
y = -2x + 150
Step-by-step explanation:
y2 - y1 / x2 - x1
120 - 100 / 15 - 25
20 / -10
= -2
y = -2x + b
100 = -2(25) + b
100 = -50 + b
150 = b