1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gnom [1K]
3 years ago
9

3.3.4 practice: modeling: factoring ax2+bx+c

Mathematics
1 answer:
deff fn [24]3 years ago
3 0
I think it should be x(ax +b) + c. Not sure though.
You might be interested in
maximize P=9x+9y Subject to 2x+y is less than or equal to 30 x+2y is less than or equal to 24 x, y is greater than 0 What is the
Inga [223]
Find the intersection point between the 2 restraint equations:
30 - 2x = 12 - \frac{1}{2} x  \\ \frac{3}{2} x = 18  \\  x = 12

Substitute back in to find y-value:
y = 30 - 2(12) = 6

P is maximized at point (12,6)
P = 9(12)+9(6) = 162
3 0
3 years ago
Is an estimate for the percent of a number always,sometimes or never greater than actual percent of the number
posledela
It would be sometimes because it can be 82.2% but if you round it the closest one would be 80% if it was 84.7% its closer to 85 so it would be 85% I hope I helped you out rate the answer if I got it right thanks!
3 0
3 years ago
birth weights in norway are normally distributed with a mean of 3570 g and a standard deviation of 500g. if the hospital officia
Svetradugi [14.3K]

Answer:

2630 g

Step-by-step explanation:

From the given information:

Given that:

mean (μ) = 3750 g

Standard deviation (σ) = 500

Suppose the hospital officials demand special treatment with a percentage of  lightest 3% (0.03) for newborn babies;

Then, the weight of birth that differentiates the babies that needed special treatment from those that do not can be computed as follows;

P(Z < z₁) = 0.03

Using the Excel Formula; =NORMSINV(0.03) = -1.88

z₁ = - 1.88

Using the test statistics z₁ formula:

z_1 = \dfrac{X-\mu}{\sigma}

-1.88 = \dfrac{X-3570}{500}

By cross multiply, we have:

-1.88 × 500 = X - 3570

-940 = X - 3570

-X = -3570 + 940

-X = -2630

X = 2630 g

Hence, 2630 g is the required weight of birth   that differentiates the babies that needed special treatment from those that do not

6 0
2 years ago
26 There is a special offer at the book shop.
Inessa [10]
10.8/12 x 100 = 90%
So he saves 10%
Add the expensive ones that equals 10.80 and then add all them together which gives you £12 you put 10.80 over 12 and multiply by 100 to find the percentage you have and then minus that from 100 which will give you your answer of 10%
6 0
2 years ago
Which math expression represents the phrase?
fiasKO [112]
"The sum of a number and 7"
Sum implies addition.
We would write this part as <em>n + 7</em>.

Then we would write the "9 times" part in like this:
<em>9 </em><em>·</em><em> </em><em>(n + 7)</em><em>
</em>We can't write just 9 · n + 7 without the parentheses, because then we would be multiplying just 9 and n instead of 9 and the sum of n and 7. (order of operations says we must do multiplication first)
5 0
3 years ago
Other questions:
  • Find the next term of the following sequence.<br><br> 25, 10, 4, ...
    11·2 answers
  • What is the value of x? 3 6 27 72
    7·1 answer
  • A squared minus 1/4 is 0. solve for a
    10·1 answer
  • How do you turn 0.8 into a fraction
    6·2 answers
  • Jocelyn estimates that a piece of wood measures 5.5 cm. If it actually measures 5.62 cm, what is the percent error of Jocelyn’s
    10·1 answer
  • What number is a factor of 8 but not a multiple of 4
    10·1 answer
  • Determine whether 8x + 18 + x is equivalent to 9(2+x) Complete the sentence to justify your answer
    15·2 answers
  • The perimeter of a notebook is 44 inches the notebook is 10 inches wide how tall is it?
    5·1 answer
  • In a class of 33 pupils, there were 3 girls who were in the school quiz team and 14 boys who were not in the school quiz team. (
    12·1 answer
  • Please solve<br><br> ??-3/10=1/5
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!