The answer is 121,434,796.00165
Answer:

Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by

where:
- f(t) is the remaining quantity of a substance after time t has elapsed.
- a is the initial quantity of this substance.
- T is the half-life
since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:

reduce fraction:

By using calculator we acquire:

hence, the remaining sample after 420 days is 0.625 kg
Answer: 6
Step-by-step explanation:
(41--1)/ (8-1) = 42/7 = 6
Answer:
=3
=2
Step-by-step explanation:
12−5+6=0
using the Quadratic Formula where
a = 1, b = -5, and c = 6
=−±2−4‾‾‾‾‾‾‾‾√2
=−(−5)±(−5)2−4(1)(6)‾‾‾‾‾‾‾‾‾‾‾‾‾‾√2(1)
=5±25−24‾‾‾‾‾‾‾√2
=5±1‾√2
The discriminant 2−4>0
so, there are two real roots.
Simplify the Radical:
=5±12
=62=42
which becomes
=3
=2
hope this helps :)
Answer:
9 lb 3 oz
Step-by-step explanation:
(3 + 5) lb + (9 + 10) oz
8 lb + 19 oz
16 oz = 1 lb
(8 + 1) lb + (19 - 16) ox
9 lb 3 oz