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LenaWriter [7]
4 years ago
15

Declining skill or fitness level from taking a break from exercise is formally referred to as (3 points) a. progression b. speci

ficity c. overload d. reversibility
Physics
1 answer:
goldenfox [79]4 years ago
6 0
The correct answer would be C because declining a break from exercise is considered overload.
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A 220g mass is on a frictionless horizontal surface at the end of a spring that has a force constant of 7.0N/m The mass is displ
sladkih [1.3K]

Answer:

Explanation:

Your numbers seem wonky, so I'll just assume that the initial displacement is a distance A (Amplitude) from the equilibrium position. Spring constant = k

Initial potential energy is

PE = ½kA²

As potential energy and kinetic energy are constantly exchanging in SHM,

the position x where half of the original spring potential exists is found where

½kx² = ½(½kA²)

    x² = ½A²

    x = (√0.5)A

    x ≈ 0.707A

just plug in your actual starting position A

With A = 5.2 cm

x = 3.67695... 3.7 cm

5 0
3 years ago
A loop of wire in the shape of a rectangle rotates with a frequency of 284 rotation per minute in an applied magnetic field of m
yaroslaw [1]

Answer:

a) Magnitude of maximum emf induced = 0.0714 V = 71.4 mv

b) Maximum current through the bulb = 0.00793 A = 7.93 mA

Explanation:

a) The induced emf from Faraday's law of electromagnetic induction is related to angular velocity through

E = NABw sin wt

The maximum emf occurs when (sin wt) = 1

Maximum Emf = NABw

N = 1

A = 4 cm² = 0.0004 m²

B = 6 T

w = (284/60) × 2π = 29.75 rad/s

E(max) = 1×0.0004×6×29.75 = 0.0714 V = 71.4 mV

Note that: since we're after only the magnitude of the induced emf, the minus sign that indicates that the induced emf is 8n the direction opposite to the change in magnetic flux, is ignored for this question.

b) Maximum current through the bulb

E(max) = I(max) × R

R = 9 ohms

E(max) = 0.0714 V

I(max) = ?

0.0714 = I(max) × 9

I(max) = (0.0714/9) = 0.00793 A = 7.93 mA

Hope this Helps!!

8 0
3 years ago
What causes the frequency of a wave<br> to increase?<br> Adding energy<br> Decreasing energy
andrey2020 [161]
The data convincingly show that wave frequency does not affect wave speed. An increase in wave frequency caused a decrease in wavelength while the wave speed remained constant. ... Rather, the speed of the wave is dependent upon the properties of the medium such as the tension of the rope. THUS, the answer is "Decreasing Energy"
4 0
4 years ago
Read 2 more answers
a parachutist weighs 1000N. when she opens her parachute, it pulls upwards on her with a force of 2000N. (a) draw a diagram to s
wel

(a) See attached figure

There are only two forces acting on the parachutist:

- Its weight, downward, of magnitude 1000 N, indicated with (mg) in the diagram (where m = mass and g = acceleration of gravity)

- The air resistance on the parachute, upward, of magnitude 2000 N, indicated with R in the diagram

The magnitude of the air resistance is twice that of the weight, therefore in the diagram is shown with an arrow approximately twice as long as the arrow representing the weight.

(b) +1000 N

Taking upward as positive direction, the two forces can be written as:

R = +2000 N

mg = -1000 N

Since the two forces are along the same line, we can find their resultant by simply calculating their algebraic sum:

F=R+mg=+2000+(-1000)=+1000 N

And the positive sign indicates that the direction is upward.

(c) The parachutist will slow down (accelerates upward)

Since there is a net force acting on the parachutist, there is also an acceleration, which can be calculated using Newton's second law:

F=ma \rightarrow a=\frac{F}{m}

where

F = +1000 N is the net force

m is the mass of th parachutist

The mass can be found from the weight:

m=\frac{mg}{g}=\frac{1000}{9.8}=102 kg

Therefore, the acceleration is

a=\frac{+1000}{102}=+9.8 m/s^2

And the direction of the acceleration is upward, while the direction of motion of the parachutist is downward: therefore, the parachutist will slow down.

4 0
3 years ago
What two element is present in biotite mica that is not present in muscovite mica?
lara31 [8.8K]

Potassium iron magnesium aluminum silicate hydroxide and Potassium magnesium aluminum silicate hydroxide.

3 0
3 years ago
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