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dezoksy [38]
3 years ago
9

Without effective assessment methods, teachers have no documented proof of childrens specific ____ and _____.

Physics
1 answer:
schepotkina [342]3 years ago
8 0

Answer:

D strengths and weakneses

Explanation:

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A proton is projected into a magnetic field that is directed along the positive x axis. Find the direction of the magnetic force
bulgar [2K]

Te direction of the magnetic force for the velocity of the proton in the

-ve  y direction will be +ve z direction.

As we know that the right-hand rule is based on the relation of magnetic fields and the forces that they exert on moving charges.When a charged particle moves under a magnetic field, it exerts a force on the particle, which is not in the same direction but different than the direction of the magnetic field.Under the right-hand rule,  if we point our pointer finger in the direction of the charged particle is moving and the middle finger is representing the direction of the magnetic field then our thumb depicts the direction of the magnetic force which is exerted on the charged particle.

So,  we are given that the direction of the velocity of the proton is in the negative y direction and the direction of the magnetic field is in the positive x  direction,  so the magnetic force is acting in the positive z direction.

To know  more about the right-hand rule refer to the link brainly.com/question/9750730?referrer=searchResults.

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4 0
1 year ago
A six pack of your favorite beverage (12 fl. oz. cans, assumed to have the same characteristics as water) is placed in a cooler
nasty-shy [4]

Answer:

Q = 169 BTU

Explanation:

As we know that volume is given as

V = 12 Fl oz

so it is given in liter as

V = 12 fl oz = 0.355 Ltr

now we have six pack of such volume

so total volume is given as

V = 6\times 0.355 Ltr

V = 2.13 ltr

so its mass is given as

m = 2.13 kg

now the change in temperature is given as

\Delta T = 70 - 34 = 36 ^oF

\Delta T = 20^oC

now the heat given to the liquid is given as

Q = ms\Delta T

Q = 2.13(4186)(20)

Q = 1.78 \times 10^5 J

Q = 169 BTU

4 0
3 years ago
The force of gravity acting<br> on a child's mass on earth is 490 newtons. what's the child's mass?
UNO [17]
F = m • a

What we know:
- Gravity: 9.8 m/s
- Force: 490 N

Equation derived:
m = F/a
m = 490/9.8
= 50 kg
6 0
3 years ago
Read 2 more answers
an astronaut drops a hammer and an egg while standing on the surface of the moon. which one will the surface first?
elena-s [515]
The two will fall at the same speed and reach the surface at the same time. This is because the two will experience the same gravitational acceleration on the moon. However, on the earth surface the two will land on the surface of the earth at the same time due to air resistance such that the egg will experience a higher air resistance than the hammer. On, the moon, where there is no noticeable atmosphere there is no air resistance on either object and both fall at the same speed. It is also important to note that their mass doesn't affect their speed.
7 0
3 years ago
Read 2 more answers
Rearrange the equation to solve for the permeability of free space (μ0). Remember that the slope is the ratio of magnetic field
IRINA_888 [86]

Complete Question

The complete question is shown on the first uploaded image

Compare the percent error between your value and the accepted value of 1.26 times 10-6 T · m/A. (Use the accepted value given to three significant figures in your calculation.). 100% % error = %

Answer:

The permeability of free space is \mu_0 = 1.32*10^{-6} \ Tm/A

The percentage error is  % error = 5.25%

Explanation:

From the question we are told that

            The slope is  s= 3.9\  G/A , and

Generally  1 \ gauss =  10^{-4 } tesla

               So  s = 3.9 *10^ {-4} T /A

From the relation given in the question

                        \mu_0 = \frac{2R}{N} [\frac{B}{I} ]

 Where R is the radius of the coil  =\frac{Diameter \ of \ coil }{2} = 0.017m

             N is the number of loops of the coil = 10

Now from the question we are told that

                  s = \frac{B}{I}

substituting into the equation above

               \mu_0 = \frac{2R }{N} s

Substituting values

              \mu_0= \frac{2 * 0.017}{10 } * 3.9*10^{-4}

                   = 1.326 *10^ {-6} \ Tm/A

Generally the % error is mathematically represented as

                    %error = \frac{Measured \  value - accepted \ value}{accepted \  value } *100

Given that the accepted value is \mu_o_ {acc} = 1.26 *10 ^{-6} \ T \cdot m /A

      Hence substituting values

                      %error  = \frac{(1.326-1.26)*10^{-6}}{1.26 *10 ^ {-6}} *100

                                  = 5.24

6 0
3 years ago
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