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Tpy6a [65]
3 years ago
10

The _________ principle states that the net electrical force on a specific charge is equal to the sum of the vector components o

f the charges applying forces on it.
Physics
2 answers:
Phoenix [80]3 years ago
8 0

Answer:

The <u>superposition</u> principle states that the net electrical force on a specific charge is equal to the sum of the vector components of the charges applying forces on it.

worty [1.4K]3 years ago
5 0
<h2>Answer: Superposition</h2><h2 />

The  superposition principle comes as a consequence of the <u>Coulomb's Law</u>, which describes <u>the force between two punctual electrical charges at rest</u>. However, Coulomb's law does not tell us anything about what happens if we have <u>more than two electrical charges</u> or if they are not punctual.

For example, if we have three charges aligned and we want to find the force on one of the ends and how the presence of the central electrical charge influences. The evidence from the experiments has shown that this central charge does not affect the force between them, and this can be expressed by the superposition principle which, in other words, is:

<em>Given a system of punctual charges, the electric force on each of them is the vector sum of the forces due to each of the other charges, as if the rest of the charges were not present. </em>

That is, we can calculate each term by Coulomb's law ignoring completely the existence of other charges.

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Explanation: on the e2020 test its right

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Gravity is the correct answer.

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When two resistors are wired in series with a 12 V battery, the current through the battery is 0.33 A. When they are wired in pa
MA_775_DIABLO [31]

Answer:

If R₂=25.78 ohm, then R₁=10.58 ohm

If R₂=10.57 then R₁=25.79 ohm

Explanation:

R₁ = Resistance of first resistor

R₂ = Resistance of second resistor

V = Voltage of battery = 12 V

I = Current = 0.33 A (series)

I = Current = 1.6 A (parallel)

In series

\text{Equivalent resistance}=R_{eq}=R_1+R_2\\\text {From Ohm's law}\\V=IR_{eq}\\\Rightarrow R_{eq}=\frac{12}{0.33}\\\Rightarrow R_1+R_2=36.36\\ Also\ R_1=36.36-R_2

In parallel

\text{Equivalent resistance}=\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\Rightarrow {R_{eq}=\frac{R_1R_2}{R_1+R_2}

\text {From Ohm's law}\\V=IR_{eq}\\\Rightarrow R_{eq}=\frac{12}{1.6}\\\Rightarrow \frac{R_1R_2}{R_1+R_2}=7.5\\\Rightarrow \frac{R_1R_2}{36.36}=7.5\\\Rightarrow R_1R_2=272.72\\\Rightarrow(36.36-R_2)R_2=272.72\\\Rightarrow R_2^2-36.36R_2+272.72=0

Solving the above quadratic equation

\Rightarrow R_2=\frac{36.36\pm \sqrt{36.36^2-4\times 272.72}}{2}

\Rightarrow R_2=25.78\ or\ 10.57\\ If\ R_2=25.78\ then\ R_1=36.36-25.78=10.58\ \Omega\\ If\ R_2=10.57\ then\ R_1=36.36-10.57=25.79\Omega

∴ If R₂=25.78 ohm, then R₁=10.58 ohm

If R₂=10.57 then R₁=25.79 ohm

6 0
3 years ago
If 230 W of power is produced in 10 seconds, how much work is done?
liq [111]

Answer:

Hello There!!

Explanation:

Use this equation:Work done = Force x Distance.

Work done=230W×10s

Work done=2300J

hope this helps,have a great day!!

~Pinky~

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<h3><u>Answer;</u></h3>

= 21600 Joules or 21.6 Kilo joules

<h3><u>Explanation;</u></h3>

Electrical energy is given by the formula  = VIt ;

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4 0
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