The standard form of the equation of a parabola is v=7x^2+14x+4

Mathematics

2 answers:

barxatty [35]3 years ago

6 0

Complete the squaer

gropu x terms
y=(7x²+14x)+4
factor out quadratic coefient
y=7(x²+2x)+4
take 1/2 of the linear coefieint and squaer it
2/2=1, (1)²=1
add positive and negiatve of it inside parnthaees
y=7(x²+2x+1-1)+4
factor perefect square trinomial
y=7((x+1)²-1)+4
distribute
y=7(x+1)²-7+4
y=7(x+1)²-3

answer is C

Maksim231197 [3]3 years ago

5 0

Answer should be C. If you simplify the vertex equation y=7(x+1)^2 -3, you end up with the standard equation.

y=7(x^2 + 2x + 1) -3
y= 7x^2 + 14x + 7 - 3
y= 7x^2 + 14x + 4

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One sample has Aa Aa One sample has n 10 scores and a variance of s2 20, and a second sample has n 15 scores and a variance of s

siniylev [52]

Answer:

option (a) It will be closer to 30 than to 20

Step-by-step explanation:

Data provided in the question:

For sample 1:

n₁ = 10

variance, s₁² = 20

For sample 2:

n₂ = 15