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Bad White [126]
3 years ago
6

The standard form of the equation of a parabola is v=7x^2+14x+4

Mathematics
2 answers:
barxatty [35]3 years ago
6 0
Complete the squaer

gropu x terms
y=(7x²+14x)+4
factor out quadratic coefient
y=7(x²+2x)+4
take 1/2 of the linear coefieint and squaer it
2/2=1, (1)²=1
add positive and negiatve of it inside parnthaees
y=7(x²+2x+1-1)+4
factor perefect square trinomial
y=7((x+1)²-1)+4
distribute
y=7(x+1)²-7+4
y=7(x+1)²-3

answer is C
Maksim231197 [3]3 years ago
5 0
Answer should be C. If you simplify the vertex equation y=7(x+1)^2 -3, you end up with the standard equation.

y=7(x^2 + 2x + 1) -3
y= 7x^2 + 14x + 7 - 3
y= 7x^2 + 14x + 4
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Given: ΔPSQ, PS = SQ Perimeter of ΔPSQ = 50 SQ – PQ = 1 Find: Area of ΔPSQ
Lana71 [14]

Answer:

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Step-by-step explanation:

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50 = SQ + SQ + (SQ -1)

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The midpoint of the base is one leg of the right triangle whose other leg is the height of this isosceles triangle. That height is ...

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