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3 years ago

The standard form of the equation of a parabola is v=7x^2+14x+4

Mathematics

2 answers:

barxatty [35]3 years ago

6 0

Complete the squaer

gropu x terms
y=(7x²+14x)+4
factor out quadratic coefient
y=7(x²+2x)+4
take 1/2 of the linear coefieint and squaer it
2/2=1, (1)²=1
add positive and negiatve of it inside parnthaees
y=7(x²+2x+1-1)+4
factor perefect square trinomial
y=7((x+1)²-1)+4
distribute
y=7(x+1)²-7+4
y=7(x+1)²-3

answer is C

Maksim231197 [3]3 years ago

5 0

Answer should be C. If you simplify the vertex equation y=7(x+1)^2 -3, you end up with the standard equation.

y=7(x^2 + 2x + 1) -3
y= 7x^2 + 14x + 7 - 3
y= 7x^2 + 14x + 4

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3 years ago

The perimeter of a rectangle is 44 inches. If the width of the rectangle is four more than half the length, find the length of t

Mars2501 [29]

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Step-by-step explanation:

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10 months ago

The oblique pyramid has a square base. What is the volume of the pyramid? 2.5 cm3 5 cm3 6 cm3 7.5 cm3

Olenka [21]

Take a look at the attachment below. It fills in for the attachment that wasn't provided in the question -

An oblique pyramid is one that has a top not aligned with the base. Due to this, the height of the pyramid connects with two vertices at its ends to form a right angle present outside the pyramid, knowing that it is always perpendicular to the base. There is no difference between the calculations of the volume of an oblique pyramid and a pyramid however -

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2 years ago

Is X-1 a factor of x^5-1?

Musya8 [376]

Answer: No

Explanation:

According to factor theorem, if f(x)=0 then x is a factor of the given function or equation.

As x-1 is a factor

We equate x-1=0

x=1

Substituting in x^5-1, we have 1^5-1 =1-1=0.

Hence, it's a factor.

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1. True
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