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Fantom [35]
3 years ago
9

Consider the compound inequality x < 4 and x>a. If a=4 and the compounding word were "or" instead of "and",what would the

solution be?Explain your answer
Mathematics
1 answer:
FinnZ [79.3K]3 years ago
4 0

Answer:

We have:

x < 4 AND x > a.

if a = 4 and we use an "or" instead of the "and" we have:

x < 4 or x > 4.

This is:

"x is larger than 4 or smaller than 4."

Then the solution of this is all the real numbers except the value x = 4.

The set of solutions can be written as:

{xI x ∈ R  \ [4]}

Where this reads:

"x belongs to the set of the reals minus the number 4".

Or we also could write it as:

x ∈ (-∞, 4) ∪ (4, ∞)

Where we have two open ends in the "4" side, so the value x = 4 does not belong to that set.

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A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the
LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1

The probability that at most 12 ties are too tight is P=1.

5 0
3 years ago
The length of a rectangle is 3 cm less than twice the width. If the perimeter is 42 cm, what is the length of the rectangle?
larisa [96]

Answer:

The length is 13

Step-by-step explanation:

w+w+l+l= perimeter

if the length is 3m less than twice the width then let's do some math.

42 divided 2 =21. so the width and length of one side have to equal 21. For example, let's use 8 as the width. The length would be twice(16) minus three(13) 13 plus 8 is 21. WOW it equals half of it so no we know the length is 13 and the wdith is 8.

6 0
3 years ago
How to find the angle
diamong [38]
I think you mean area !!

4 0
3 years ago
What is the GCF of 48x4 and 44x5
zepelin [54]
The GCF would be : 4x^4
8 0
3 years ago
The ratio of the length 2.0 meters to the length 1.2 meters is
photoshop1234 [79]

Answer:

The Ration of length 2.0 meters  to the length 1.2 meters = 5 : 3

Step-by-step explanation:

The given two length are 2.0 m  and 1.2 m

Length L1 = 2.0 m     And

Length L2 = 1.2 m

SO, The ratio of L1 : L2 = \frac{2.0}{1.2}

Or, The ratio of L1 : L2 =  \frac{20}{12}

∴    The ratio of L1 : L2 =  \frac{5}{3}

Hence The ratio of L1 : L2 is 5 : 3    Answer

4 0
4 years ago
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