Answer:
perimeter is 4 sqrt(29) + 4pi cm
area is 40 + 8pi cm^2
Step-by-step explanation:
We have a semicircle and a triangle
First the semicircle with diameter 8
A = 1/2 pi r^2 for a semicircle
r = d/2 = 8/2 =4
A = 1/2 pi ( 4)^2
=1/2 pi *16
= 8pi
Now the triangle with base 8 and height 10
A = 1/2 bh
=1/2 8*10
= 40
Add the areas together
A = 40 + 8pi cm^2
Now the perimeter
We have 1/2 of the circumference
1/2 C =1/2 pi *d
= 1/2 pi 8
= 4pi
Now we need to find the length of the hypotenuse of the right triangles
using the pythagorean theorem
a^2+b^2 = c^2
The base is 4 ( 1/2 of the diameter) and the height is 10
4^2 + 10 ^2 = c^2
16 + 100 = c^2
116 = c^2
sqrt(116) = c
2 sqrt(29) = c
Each hypotenuse is the same so we have
hypotenuse + hypotenuse + 1/2 circumference
2 sqrt(29) + 2 sqrt(29) + 4 pi
4 sqrt(29) + 4pi cm
Answer:
Step-by-step explanation:
t=(-2.74 + sqrt(2.74^(2)-4*-4.9*(-10))) / -2*-4.9
t=(-2.74 + sqrt(7.5076-4*+49))/9.8
t=(-2.74 + sqrt(7.5076+45))/9.8
t=(-2.74 + sqrt(52.5076))/9.8
t=(-2.74/9.8)+(sqrt(52.5076))/9.8
this is simplest form, next will be rounded answers
t=0.45981763305
<span>85 x 63 = 5355
hope it helps
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So firstly, you want to foil - (7v^4 + 6) [Think of the minus sign as -1]: 
Next, combine like terms and your answer will be: 
Answer:
-2/9
Step-by-step explanation: