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Alexxandr [17]
3 years ago
15

That’s what I need to know to set it up plzzzzss help

Mathematics
2 answers:
AURORKA [14]3 years ago
7 0
3×(60+7)
(3×30) + (3×7)
90 + 21 = 111
omeli [17]3 years ago
5 0
3 times 60+7.
I hoped this helped
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Write the equation of the line that passes through (1, 3) and has a slope of 2 in point-slope form. (2 points) y − 1 = 2(x − 3)
NARA [144]

Answer:

  y − 3 = 2(x − 1)

Step-by-step explanation:

The point-slope form of the equation of a line with slope m through point (h, k) is ...

  y -k = m(x -h)

You have m=2, h=1, k=3, so the equation is ...

  y -3 = 2(x -1)

8 0
3 years ago
xia has 16 meters of rope. She cuts off 1/6 of the rope to use as a skipping rope for a party activity. how long is xias skippin
katrin2010 [14]

\frac{1}{6}  \times 16 =  \frac{8}{3}  = 2.67m
So, Xia's skipping rope is 2.67m long.
6 0
3 years ago
Read 2 more answers
How do you find DE, Round to nearest 10th
Sergeu [11.5K]

Answer:  DE\approx6.0

Step-by-step explanation:

Observe in the figure given in the exercise that four right triangles are formed.

In this case you can use the following Trigonometric Identity to solve this exercise:

cos\alpha=\frac{adjacent}{hypotenuse}

From the figure you can identify that:

\alpha =53\°\\\\hypotenuse=10\\\\adjacent=BE=DE

Then, you can substitute values:

cos(53\°)=\frac{DE}{10}

The next step is to solve for DE in order to find its value. This is:

10*cos(53\°)=DE\\\\DE=6.01

Finally, rounding the result to the nearest tenth, you get that this is:

DE\approx6.0

7 0
3 years ago
A chef buys 9cucumbers,18 peppers, and 21 tomatoes at the farmer's market. How much does she spend?
stepladder [879]
HAY THERE!

ACCORDING TO QUESTION:-
Cucumbers = 6 for $2
Peppers = 12 for $9
Tomatoes = 6 fir $4
____________
SO NOW
____________
\huge{SOLUTION:- }
____________
For 9 cucumbers = as 6 cucumbers is for $2 then 9 will be of $3........1️⃣

For 18 peppers = as 12 peppers are for$9 so 18 will be of $12.........2️⃣

For 21 tomatoes =as 6 tomatoes are for $4 then 21 tomatoes are $14 .......3️⃣

Now add 1️⃣ +2️⃣ + 3️⃣

here $3 +$12 + $14= $29

HOPE IT HELPED YOU.
6 0
3 years ago
A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len
Gnom [1K]

Answer:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

df=n-1=93-1=92  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

\bar X=5.97 represent the sample mean for the length

s=0.4 represent the sample standard deviation

n=93 sample size  

\mu_o =6 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:  

Null hypothesis:\mu = 6  

Alternative hypothesis:\mu \neq 6  

since we don't know the population deviation the statistic is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing in formula (1) we got:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

P value

The degrees of freedom are given by:

df=n-1=93-1=92  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

5 0
3 years ago
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