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Alexxandr [17]
3 years ago
15

That’s what I need to know to set it up plzzzzss help

Mathematics
2 answers:
AURORKA [14]3 years ago
7 0
3×(60+7)
(3×30) + (3×7)
90 + 21 = 111
omeli [17]3 years ago
5 0
3 times 60+7.
I hoped this helped
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ruslelena [56]
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If a rocket is propelled upward from ground level, its height in meters after t seconds is given by h= -9.8t^2 + 107.8t. During
Rudik [331]

Answer:

5

Step-by-step explanation:

We know that the function of the height of a rocket after t seconds is:

h(t)=-9.8t^2+107.8t

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So, substitute 294 for h(t) and solve for t:

294=-9.8t^2+107.8t

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t^2-11t+30=0

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Zero Product Property:

t-6=0\text{ or } t-5=0

Solve for each equation:

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So, our answers are 5 seconds and 6 seconds.

Therefore, <em>between</em> the fifth and sixth second, the rocket is higher than 294 meters.

Note that at exactly the fifth and sixth second, our height is exactly 294 meters, not higher.

Therefore, we won't include 5 and 6 in our solution set.

As an inequality, this is:

5

In interval notation, this is:

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3 years ago
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Answer:

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