Answer:
Perimeter = 12+4pi
Area = 16+8pi
Step-by-step explanation:
Description of the assumed shape:
A rectangle 2 x 8 superimposed on a semi-circle of radius 4.
Perimeter:
P = 2+8+2+(4)(pi) = 12+4pi
Area :
A = 2*8 +(pi)4^2/2 = 16 + 8pi

Here, we want to find the diagonal of the given solid
To do this, we need the appropriate triangle
Firstly, we need the diagonal of the base
To get this, we use Pythagoras' theorem for the base
The other measures are 6 mm and 8 mm
According ro Pythagoras' ; the square of the hypotenuse equals the sum of the squares of the two other sides
Let us have the diagonal as l
Mathematically;
![\begin{gathered} l^2=6^2+8^2 \\ l^2\text{ = 36 + 64} \\ l^2\text{ =100} \\ l\text{ = }\sqrt[]{100} \\ l\text{ = 10 mm} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20l%5E2%3D6%5E2%2B8%5E2%20%5C%5C%20l%5E2%5Ctext%7B%20%3D%2036%20%2B%2064%7D%20%5C%5C%20l%5E2%5Ctext%7B%20%3D100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%2010%20mm%7D%20%5Cend%7Bgathered%7D)
Now, to get the diagonal, we use the triangle with height 5 mm and the base being the hypotenuse we calculated above
Thus, we calculate this using the Pytthagoras' theorem as follows;
Step-by-step explanation:
4x² - 12x + 17 = 0
i is an imaginary number and it equals √-1, and you usually put it when the number under the root is negative.
So √-5 = √5i and √-4 = 2i
3y=4x-27
y=4/3x-9
That’s how you do the equation