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andrew-mc [135]
3 years ago
12

Some rectangular tiles measure 15 cm by 9 cm . What is the length of the side of the smallest square area that can be covered by

these tiles? PLS HELP
Mathematics
1 answer:
vazorg [7]3 years ago
6 0

Answer:

45 cm

Step-by-step explanation:

Find LCM(15,9). First factor both numbers:

15=3\cdot 5\\ \\9=3\cdot 3

So,

LCM(15,9)=3\cdot 5\cdot 3=45

This means that the length of the side of the smallest square area that can be covered by these tiles is 45 cm.

Practically, you can put 3 tiles in a row (to make 3 lenghts of 15 cm each that add up to 45 cm) and put such 5 rows (to make 5 lengths of 9 cm that add up to 45 cm).

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If x=2, y=3 and z=1 then find the value of <br> 1/2 x + 3/4 y
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JL = 28,<br> KL= 5x + 6, and<br> JK = 3x + 6,
Alexeev081 [22]

Answer:

KL = 16

Step-by-step explanation:

For this problem, JL is the sum of KL and JK.  So we can say this:

JK + KL = JL

( 3x + 6 ) + ( 5x + 6 ) = 28

8x + 12 = 28

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x = 2

So, now we can find KL:

5x + 6 = ?

5(2) + 6 = ?

10 + 6 = ?

16 = ?

So the length of KL is 16.

Cheers.

7 0
3 years ago
I need an answer please! The question says Find the value of x that would make the following expression equivalent to sixteen ti
aev [14]
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The square root of 1536 is equal to 39.19

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