What is the y-intercept of this quadratic function f(x) = x2 + 2x + 3
2 answers:
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Answer:
vertex = (- 5, - 8)
Step-by-step explanation:
Given a quadratic in standard form : ax² + bx + c = 0 : a ≠ 0
Then the x- coordinate of the vertex is
= -
Given x² + 10x = - 17 ( add 17 to both sides )
x² + 10x + 17 = 0 ← in standard form
with a = 1, b = 10, c = 17, then
= -
= - 5
Substitute x = - 5 into the quadratic for the corresponding value of y
y = (- 5)² + 10(- 5) + 17 = 25 - 50 + 17 = - 8
Hence vertex = (- 5, - 8)