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Natali5045456 [20]
3 years ago
9

PLEASE HELP I WILL MARK BRAINLIEST

Mathematics
1 answer:
Andreas93 [3]3 years ago
6 0

Answer:

Step-by-step explanation:

LOL

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Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and st
SashulF [63]

Answer:

0.7233

Step-by-step explanation:

We want to find the area between the z-scores z=-0.95 and z=1.25.

We first find the area to the left of each z-score, and subtract the smaller area from the bigger one.

For the area to the left of z=-0.95, we read -0.9 under 5 from the standard normal distribution table.

This gives P(z<-0.95)=0.1711

Similarly the area to the left of z=1.25 is

P(z<1.25)=0.8944

Now the area between the two z-scores is

P(-0.25<z<1.25)=0.8944-0.1711=0.7233

7 0
3 years ago
What is 4x(3/5)+(3-98)=
Darya [45]
It would be 2.4x+(-95)=
3 0
4 years ago
Read 2 more answers
-5x-(-7-4x)=-2(3x-4) true?
qwelly [4]

Answer:

x=1/5

Step-by-step explanation:

-5x-(-7-4x)=-2(3x-4)

-5x+7+4x=-6x+8

-5x+4x+7=-6x+8

-x+7=-6x+8

-x-(-6x)+7=8

-x+6x+7=8

5x+7=8

5x=8-7

5x=1

x=1/5

8 0
3 years ago
Running times for 400 meters are Normally distributed for young men between 18 and 30 years of age with a mean of 93 seconds and
Luda [366]

Answer:

C. 45 and 141 seconds

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 93 seconds

Standard deviation = 16 seconds

99.7% of running times are approximately between:

By the Empirical rule, within 3 standard deviations of the mean, so between 3 standard deviations below the mean and 3 standard deviations above the mean

3 stnadard deviations below the mean

93 - 3*16 = 45 seconds

3 standard deviations above the mean

93 + 3*16 = 141 seconds

The correct answer is:

C. 45 and 141 seconds

3 0
3 years ago
Listed below are the overhead widths​ (in cm) of seals measured from photographs and the weights​ (in kg) of the seals. Construc
Anarel [89]

Answer and Step-by-step explanation: Scaterplot is a type of graphic which shows the relationship between to variables. In this question, you want to determine if there is a linear relationship between overhead widths of seals and the weights. So, the hypothesis are:

H₀: no linear correlation;

H₁: there is linear correlation;

In this hypothesis test, to reject H₀, the correlation coefficient r of the data set has to be bigger than the critical value from the table.

With α = 0.05 and n = 6, the critical value is 0.811.

The linear correlation is calculated as:

r = n∑xy - ∑x.∑y / √[n∑x² - (∑x)²] [n∑y² - (∑y)²]

r = \frac{6.9632 - 51.1108}{\sqrt{6.439 - (51^{2} )}.6.14482 - (1108^{2} ) }

r = 0.9485

Since r is bigger than the critical value, H₀ is rejected, which means there is enough evidence to conclude that there is linear correlation between overhead widths and the weights.

In the attachments is the scaterplot of the measurements, also showing the relationship.

5 0
4 years ago
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