<span>[ (1 / 36) - (1 / x²) ] / [ (1 / 6) + (1 / x) ]
[ (x² - 36) / 36x² ] / [ (x + 6) / 6x ]
</span>remember that<span>:
x² - 36 = (x + 6)(x - 6)
so
[ (x+6)(x-6) / 36x² ] / [ (x + 6) / 6x ]
[ (x+6)(x-6) / 36x² ] * [ 6x / (x + 6) ]
6x / 36x² = 1 / 6x
[ (x+6)(x-6) / 6x ] * [ 1 / (x+6) ] -------------------- > </span>(x - 6) / 6x<span>
The answer is </span>(x - 6) / 6x<span>
</span>
Need more context to answer this question. Please send me the rest of the context
Answer:
1 / 2704
Step-by-step explanation:
Number of cards in a deck = 52
9 of clubs in a deck = 1
10 of clubs in a deck = 1
Probability = required outcome / Total possible outcomes
P(9 of club) = 1 / 52
With replacement ;
Then ;
P(10 of club) = 1 / 52
Hence,
P(9 of club, then 10 of club) = 1/52 * 1/52 = 1 / 2704
Hello, Marymack!
We know that in a geometric sequence defined by
and
, the sum can be calculated the following way:
