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Natalka [10]
3 years ago
11

Two cards are dealt at random from a standard deck of 52 cards. What is the probability that the first card is a King and the se

cond card is a $\heartsuit$
Mathematics
1 answer:
34kurt3 years ago
5 0

Answer:

1 / 51

Step-by-step explanation:

Given that :

Number of cards in a deck = 52

Number of heart suit = 13

Number of kings = 4

Recall:

Probability = (required outcome / Total possible outcomes)

P(first card is king) = 4/52 = 1/13

P(second card is heart) = 13/51

Hence,

P(first card is king) * P(second card is heart)

(1/ 13) * (13/51) = 13 / 663 = 1/ 51

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Step-by-step explanation:

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23pi/8

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Find the values of x and y.
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4x+5x = 90
9x = 90
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answer
<span>d) x = 10, y = 12</span>
5 0
3 years ago
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Which represents the inverse of the function<br> f(x) = 4x?
hram777 [196]

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Step-by-step explanation:

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ATA movie theater the size of popcorn has decreased by 10%. If the old bag held 14 cups how much does the new bag hold
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3 0
3 years ago
Which of the following statements is true if m∠E = m∠Y and m∠F = m∠X?
mars1129 [50]

Answer:

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX

Step-by-step explanation:

see the attached figure to better understand the problem  

we know that  

If m∠E = m∠Y and m∠F = m∠X  

then  

Triangles EFG and YXZ are similar by AA Similarity Theorem  

Remember that  

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent  

In this problem  

The corresponding sides are  

FE and XY  

EG and YZ  

GF and ZX  

so therefore  

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX Firstly , let us learn about trigonometry in mathematics.  

Suppose the ΔABC is a right triangle and ∠A is 90°.  

sin ∠A = opposite / hypotenuse

cos ∠A = adjacent / hypotenuse

tan ∠A = opposite / adjacent

Let us now tackle the problem!  

A similar triangle has the same angle, in other words the triangle has the same shape but different sizes.  

From the figure in the attachment , we can conclude that:  

m∠E = m∠Y  

m∠F= m∠X  

m∠G = m∠Z  

∴ ΔEFG ~ ΔYXZ  ( ΔEFG is similar to ΔYXZ )    

Because of the similarity , then:  

FE : XY = EG : YZ = GF : ZX  

Conclusion:

ΔFG is similar to ΔYXZ.  

Segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX , i.e:    

Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse , Triangle , Fraction , Lowest , Function , Angle

3 0
3 years ago
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