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Alex_Xolod [135]
2 years ago
12

In case the other photo is a little blurry

Mathematics
1 answer:
vova2212 [387]2 years ago
5 0
In some instances you’ll have to opt for a really have ISO sensitivity to avoid camera shake you’re handholding your camera
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!!!! PLEASE HELP !!!!
baherus [9]
Your answer is B, (1,5)

Based on your equation, 5x means in one movement of the x axis it increases 5 spaces on the Y axis. Since there is nothing after the 5x indicating it is starting elsewhere this means it starts at 0.0. So after the first movement on the x axis your value will be 1 plug in your x axis value to the equation f(x)=5x so it will look like f(1)=5•1 and then you will have both values needed to form your answer (1,5)
4 0
2 years ago
Match each quadratic equation with its solution set.
Marianna [84]

Answer:

( 8 , - 8)  => x² - 55 = 9

( 4 , - 4)  =>  2x² - 32 = 0

(5 , - 5) => 4x² - 100 = 0

(11 , - 11) => x² - 140 = -19

( 3, - 3) =>  2x² - 18 = 0

Step-by-step explanation:

1)

2x^2  - 32 = 0\\\\2(x^2 - 16 ) = 0 \\\\x^2 - 16 = 0 \\\\x^2 = 16 \\\\x = \sqrt {16 }  = \pm 4

x = ( 4 , - 4)

2)

4x^2 - 100 = 0 \\\\4(x^2 - 25 ) = 0\\\\x^2 - 25 = 0 \\\\x^2 = 25 \\\\x= \sqrt{25} = \pm 5

x = ( 5 , - 5 )

3)

x^2 - 55 = 9 \\\\x^2 = 9 +55\\\\x^2 = 64\\\\x = \sqrt{64} = \pm 8

x= ( 8 , - 8)

4)

x^2 - 140 = - 19\\\\x^2 = -19 + 140 \\\\x^2 = 121 \\\\x= \sqrt{121} = \pm 11

x = ( 11  , -11)

5)

2x^2 - 18 = 0\\\\2(x^2 - 9) = 0\\\\x^2- 9 = 0 \\\\x^2 = 9 \\\\x = \sqrt9 = \pm 3

x = ( 3 , - 3)

8 0
3 years ago
Read 2 more answers
What is the solution to the system of equations?
Llana [10]

Solution in attachment.

<h3>x = -6, y = 9, z = -3</h3>

3 0
3 years ago
Does the equation y = x(x - 3) represent a linear function
Flauer [41]

Answer:

No

Step-by-step explanation:

No. You can see why if you remove the brackets.

y=x^2 - 3x.

A linear function must have x and y with powers of 1. Also it can't something like x^2 - y^2 = 5

x^2 - y^2 = 0 is the only exception I can think of, but that really is a system of equations. If you graph it. you get two equations which cross at 0 and nowhere else.

7 0
2 years ago
2. Lawn tickets cost $30 each and seat tickets cost $50
Andreas93 [3]
Okay so.
If lawn tickets are $30 and seat tickets are $50 and they sold 200 seat tickets.
50 multiplied by 200 is = $ 10,000
And the goal is $14,000.
So $14,000 subtract $10,000 is $4000
$4000 is how much they made in Lawn Tickets. In order to calculate how much lawn tickets were sold, is dividing $4000 by $30 since lawn tickets are $30.
4000 divided by $30 = 133
Not sure if this is correct but all the working and steps are correct! Hope this helps.
6 0
2 years ago
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