A function

is periodic if there is some constant

such that

for all

in the domain of

. Then

is the "period" of

.
Example:
If

, then we have

, and so

is periodic with period

.
It gets a bit more complicated for a function like yours. We're looking for

such that

Expanding on the left, you have

and

It follows that the following must be satisfied:

The first two equations are satisfied whenever

, or more generally, when

and

(i.e. any multiple of 4).
The second two are satisfied whenever

, and more generally when

with

(any multiple of 10/7).
It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when

is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.
Let's verify:


More generally, it can be shown that

is periodic with period

.
Well, it depends what shape you are using the volume formula for. If it's for a square (I'm assuming) then the volume formula would be:
Side^2
Answer:
no solution
Step-by-step explanation:
There are no values of x that make the equation true.
Answer:
k= -29
Step-by-step explanation:
Answer:
Solve the equation for s by finding a , b , and c of the quadratic then applying the quadratic formula.
s
=
−
2
Double roots