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maksim [4K]
3 years ago
15

If the outliers are not included, what is the mean of the data set

Mathematics
1 answer:
Naddika [18.5K]3 years ago
5 0
804÷12
=67
so the mean is 67

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There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
3 years ago
Can someone help me on this with the steps? thanks!
soldi70 [24.7K]

Answer:

8h + 15 = 39

Step-by-step explanation:

The base fee is 15 so you shouldn't multiply the hours by it.

The question states 8 per hour which means that you should multiply the 8 by hours and add on the base fee which is 15.

8 0
3 years ago
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This soda can is going to be made from aluminum. How many square centimeters of aluminum are needed if the radius r = 3.5 cm and
kari74 [83]

208.81 square centimeters of aluminium are needed

<em><u>Solution:</u></em>

Given that,

Radius = 3.5 cm

Height = 6 cm

We have to find the square centimeters of aluminum needed

So we have to find the surface area of cylinder

<em><u>The surface area of cylinder is given by formula:</u></em>

A = 2 \pi r(h+r)

Where "r" is the radius and "h" is the height of cylinder

<em><u>Substituting the values we get,</u></em>

A  = 2 \times 3.14 \times 3.5 \times (6+3.5)\\\\A = 21.98 \times 9.5\\\\A = 208.81

Thus 208.81 square centimeters of aluminium are needed

8 0
3 years ago
What is 55 divided by 1 1/2
Karolina [17]

Answer:

55 divided by 11/2 is 10

5 0
3 years ago
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(x-2)(-5x^2+x)=(x)(-5x^2)+(x)(x)+(-2)(-5x^2)+(-2)(x) is an exsample of
e-lub [12.9K]

this is an example of linear equations is one variable

6 0
3 years ago
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