All categories

3 years ago

Suppose n represents an even number for a simplified expression that represents the product of the next two even numbers

2 answers:

7 0

Next 2 even numbers
even numbers are 2 apart
2,4,6,8

so the product of the next two even numbers is
(n+2)(n+4)=n^2+6n+8

Digiron [165]3 years ago

3 0

N+1 x n+2 = whatever that first part means

You might be interested in

Which of these triangle pairs can be mapped to each other using a reflection

tia_tia [17]

Help me! I’ll mark you brainly!

8 0

3 years ago

The expression -10y²+54y+36 represents the profits made by a company when it increases the price of the product by y dollars. Fa

stiv31 [10]

Answer:

− 2( 5 y + 3 ) ( y − 6 )

Step-by-step explanation:

hope it helps

7 0

3 years ago

How do you factor binomials using difference of squares?

Ket [755]

I have solved some examples in the picture

If anything is unclear let me know.

6 0

3 years ago

If a gas-filled balloon rises 40 feet in the 1st minute, 60 feet in the 2nd minute, and 80 feet in the 3rd minute, how many feet

tresset_1 [31]

The distance traveled by the balloon in every minute makes an arithmetic sequence with a first term equal to 40 ft and common difference equal to 20. The nth term of an arithmetic sequence is calculated by,
an = a1 + (n - 1) x d
Substituting,
an = 40 + (15 - 1) x 20 = 320
Thus, the answer is letter B. 320 feet.

7 0

3 years ago

Plz write this on paper help me and send it❤️

vovangra [49]

Answer:

1. $27^{\frac{2}{3} } =9$

2. $\sqrt{36^{3} } =216$

3. $(-243)^{\frac{3}{5} } =-27$

4. $40^{\frac{2}{3}}=4\sqrt[3]{25} =4325$

5. Step 4: $(\frac{343}{27}) ^{-1} =\frac{27}{343}$

6. $D. -72cd^{7}$

Step-by-step explanation:

Use the following properties:

$a^{\frac{x}{y} } =\sqrt[x]{a^{y} }$

$\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}$

$a^{-n} =\frac{1}{a^{n} }$

$(xy)^{z} =x^{z} y^{z} \\\\$

$(x^{y}) ^{z} =x^{yz}$

$x^{y} x^{z} =x^{y+z}$

So:

1. $27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9$

2. $\sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36} \sqrt{36} =6*6*6=216$

3. $(-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27$

4. $40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325$

5. $(\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}$

$(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}$

7 0

3 years ago