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bearhunter [10]
3 years ago
7

A toy has various shaped objects that a child can push through matching holes. The area of the square hole is 14 square centimet

ers. The volume of a​ cube-shaped block is 343 cubic centimeters.
a. Which edge length can be​ found? Explain.
b. Will the block fit in the square​ hole? Explain.

a. Since (14/343) is a perfect (cube/square) the length of each edge of the (hole/block)
can be found. Each edge is __ centimeters long.
Mathematics
2 answers:
stiv31 [10]3 years ago
7 0

Answer:

I am not sure the answer but I can say this from my experiences, to know the shapes and sizes, you may measure like I usually do.  

Step-by-step explanation:

I am not sure

viktelen [127]3 years ago
4 0

Answer: Since 343 is a perfect CUBE, the length of each edge of the BLOCK can be found. Each edge is 7 centimeters long.

Step-by-step explanation: 7×7×7=343

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Answer:

Therefore the only statement that is not true is b.)

Step-by-step explanation:

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b.) The probability that a secretary wins a ticket on second draw.  It has been given that a ticket was won on the first draw by a consultant.

p(secretary wins on second draw | consultant  wins on first draw)

=\frac{p((consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)\cap( secretary\hspace{0.1cm} wins\hspace{0.1cm} on second \hspace{0.1cm}draw))}{p(consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)}

= \frac{\frac{5}{15}  \times \frac{6}{14}}{\frac{5}{15} }  = \frac{6}{14}  .

The probability that  a ticket was won on the first draw by a consultant a secretary wins a ticket on second draw  = \frac{6}{15} is not true.

The probability that a secretary wins on the second draw  = \frac{number \hspace{0.1cm} of  \hspace{0.1cm} secretaries  \hspace{0.1cm} remaining } { number  \hspace{0.1cm} of  \hspace{0.1cm} employees  \hspace{0.1cm} remaining}  = \frac{6 - 1}{15 - 1}  = \frac{5}{14}

c.) The probability that a consultant wins on the first draw  =

\frac{number \hspace{0.1cm} of  \hspace{0.1cm} consultants  \hspace{0.1cm}  } { number  \hspace{0.1cm} of  \hspace{0.1cm} employees  \hspace{0.1cm} }  = \frac{5 }{15}  = \frac{1}{3}

d.) The probability of two secretaries winning both tickets

= (probability of a secretary winning in the first draw) × (The probability that a secretary wins on the second draw)

= \frac{6}{15}  \times \frac{5}{14}  = \frac{1}{7}

Therefore the only statement that is not true is b.)

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Answer: Frequencies .

Step-by-step explanation:

In statistics theory the chi-square test statistic is calculated by considering each cell and the expected frequency is subtracted from the observed frequency after that the difference is squared, and the total is divided by the expected frequency. This is highlight that the key focus of the chi-square test is the frequencies .

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Step-by-step explanation:

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Answer:

B

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