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sesenic [268]
2 years ago
6

jose spent 6 hours in school. each school period is 3/4 hour long. how many period did jose spend in school?

Mathematics
1 answer:
34kurt2 years ago
6 0

Answer:

why are you asking me ask jose

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<img src="https://tex.z-dn.net/?f=3x%2B9%2B2x%3Dx-2x-3" id="TexFormula1" title="3x+9+2x=x-2x-3" alt="3x+9+2x=x-2x-3" align="absm
V125BC [204]

Answer:

Step-by-step explanation:

Equation

3x + 9 + 2x = x - 2x - 3              

Solution

Combine all the like terms.

3x+2x+9 =  x - 2x - 3

5x + 9 = -x - 3                            Add x to both sides of the equation

5x+x +9 = -x+x -3                      Combine

6x + 9 = - 3                                Subtract 9 from both sides of the equation

6x+9-9 = - 3-9                           Combine

6x = -12                                      Divide both sides by 6

6x/6 = -12/6

x = - 2

Answer x = - 2

3 0
2 years ago
Read 2 more answers
How to solve x÷15=11
stepan [7]

Answer:

x=165

Step-by-step explanation:

Multiply both sides by 15

15(x/15)=11*15

x=165

7 0
3 years ago
The product of (3 + 2i) and a complex number is (17 + 7i).
Vesna [10]
A+bi is a complex number

(3+2i)(a+bi)=17+7i
remember
i²=-1
so
expand and solve
a is the ral part
bi is the imaginary part
ok so
if Ac+Be=dc+fe where c=c and e=e then A=d and B=f

(3+2i)(a+bi)=17+7i
expand/distribute/FOIL
3a+2ai+3bi+2bi²=17+7i
3a+2bi+2ai+2bi=17+7i
3a-2b+2ai+2bi=17+7i
real parts are 3a-2b
imaginary is 2ai+2bi
so

3a-2b=17 and
2ai+2bi=7i

we need to solve
2nd equation, divide both sides by i
2a+2b=7
multiply by -1 and add to other equation

3a+2b=17
<u>-2a-2b=-7 +</u>
1a+0b=10
a=10

subsitue
2a+2b=7
2(10)+2b=7
20+2b=7
2b=-13
b=-13/2


the complex number is
10-(13/2)i or
10-6.5i
8 0
3 years ago
Jerome spent $20 on supplies to make 50 cookies for a bake sale. Write and solve an inequality to find the price that Jerome sho
Semenov [28]

Answer:

Each cookie will have to be sold for at least $0.90 if the profit is to be made is more than $25.

Step-by-step explanation:

The amount spent on supplies is $20.

The number of cookies baked is = 50.

If the profit to be made is more than $25.00 .

Then we can safely say that all the cookies have to be sold for

= $20.00 + $25.00

= $45.00

Therefor the required inequality can be written as

50 x ≥ $45.00            ⇒       x   ≥   \frac{45.00}{50}            ⇒      x   ≥  $0.90.

Therefore we can say that each cookie will have to be sold for at least $0.90 if the profit is to be made is more than $25.

7 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST Question 8
mote1985 [20]

Answer:

Step-by-step explanation:

a)y=-2x+8

y=4x-7

solution

b)y=x-4

y=3x-2

solution

c)x – 3y = -3

x – 3y = 6

no solution

d)3x +y = 3

6x + 2y = 6

infinite.

5 0
3 years ago
Read 2 more answers
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