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Oksi-84 [34.3K]
3 years ago
11

A jewelry store marked up the price of its well-known necklace. The new price of the necklace is $250, which is 125% of the orig

inal price. What was the original price of the necklace?
A. $125
B. $150
C. $175
D. $200
Mathematics
2 answers:
liraira [26]3 years ago
8 0
The answer would be D
Likurg_2 [28]3 years ago
3 0
D would be your answer.
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The sum of three consecutive numbers is 90. What is the largest integer?
saveliy_v [14]
The answer would be B
5 0
3 years ago
Today's high temperature is 72°F. If yesterday's high temperature was 87°F, what was the change in high temperatures? -15°F
makkiz [27]

Answer:

15°F

Step-by-step explanation:

It is given that,

Today's high temperature is 72°F and yesterday's high temperature was 87°F. We need to find the change in high temperatures.

Change in temperatures = final temperature - initial temperature

= 87°F - 72°F

= 15°F

It means that the change in temperature is 15°F. Hence, the correct option is (b).

8 0
3 years ago
Read 2 more answers
Please halp me in the question?
xz_007 [3.2K]

Answer: a. (x-6) + 5x = 90 b. Angle One = 10° Angle Two = 80°

Step-by-step explanation:

A. Since angle 1 plus angle 2 is a right angle, then their sum is 90 degrees. The equation form angle 1 is x-6 and the equation for angle 2 is 5x, so (x-6) + 5x = 90

B. To find x,

x - 6 + 5x = 90

x + 5x = 96

6x = 96

x = 16

So, angle one = (16) - 6 = 10° and angle two = 16 * 5 = 80°

5 0
3 years ago
Find the value of B of the shape
Dahasolnce [82]

Answer:

34

Step-by-step explanation:

All angles of a triangle add up to 180 degrees so you would subtract from 180 with the angles you already have to get your answer. 180 - 115 - 31 = B which is 34.

7 0
3 years ago
Find all solutions to the following equation. If there are any extraneous solutions, identify them and explain why they are extr
vagabundo [1.1K]

Answer:

b = 3, which is an extraneous solution because if we replace b = 3 in the equation, we must be 5/0 and 30/0, and there is division by 0.

Step-by-step explanation:

\frac{7}{b+3} + \frac{5}{b-3} = \frac{10b}{b^2-9}

The minus common multiply must be (b-3)*(b+3) = b² - 9

\frac{7*(b-3)}{b^2-9} + \frac{5*(b+3)}{b^2 -9}  = \frac{10b}{b^2-9}

7b - 21 + 5b + 15 = 10b

2b = 6

b = 3

Which is an extraneous solution because if we replace b = 3 in the equation, we must be 5/0 and 30/0, and there is division by 0. So this solution is invalid.

7 0
2 years ago
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