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kondaur [170]
3 years ago
9

Can someone please help me with this!!!

Mathematics
1 answer:
user100 [1]3 years ago
7 0
It is an arithmetic because it is adding 2 to each number.
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Find the standard form of the equation of the ellipse with the given characteristics. Vertices: (4, 0), (4, 14); endpoints of th
saul85 [17]

Answer:

The standard form of the ellipse is \frac{(x-4)^{2}}{9} + \frac{(y-7)^{2}}{49} = 1.

Step-by-step explanation:

The major axis of the ellipse is located in the y axis, whereas the minor axis is in the x axis. The center of the ellipse is the midpoint of the line segment between vertices, this is:

(h, k) =\frac{1}{2}\cdot V_{1} (x,y) + \frac{1}{2}\cdot V_{2} (x,y) (1)

If we know that V_{1} (x,y) = (4,0) and V_{2}(x,y) = (4, 14), then the coordinates of the center are, respectively:

(h,k) = \frac{1}{2}\cdot (4, 0) + \frac{1}{2}\cdot (4,14)

(h,k) = (2,0) + (2, 7)

(h, k) = (4, 7)

The length of each semiaxis is, respectively:

a = \sqrt{(1 - 4)^{2}+(7-7)^{2}}

a = 3

b = \sqrt{(4-4)^{2}+(0-7)^{2}}

b = 7

The standard equation of the ellipse is described by the following formula:

\frac{(x-h)^{2}}{a^{2}}+ \frac{(y-k)^{2}}{b^{2}} = 1

Where:

h, k - Coordinates of the center of the ellipse.

a, b - Length of the orthogonal semiaxes.

If we know that h = 4, k = 7, a = 3 and b = 7, then the standard form of the ellipse is:

\frac{(x-4)^{2}}{9} + \frac{(y-7)^{2}}{49} = 1

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3 years ago
If AAED AACB, which must be true?
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Answer:

I am pretty sure it's A, 85% sure

Step-by-step explanation:

Sorry wasn't a ton of help, ignore if there is a better answer but you seem like in a rush

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20 miles times 3

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