The product of two rational numbers is always rational because (ac/bd) is the ratio of two integers, making it a rational number.
We need to prove that the product of two rational numbers is always rational. A rational number is a number that can be stated as the quotient or fraction of two integers : a numerator and a non-zero denominator.
Let us consider two rational numbers, a/b and c/d. The variables "a", "b", "c", and "d" all represent integers. The denominators "b" and "d" are non-zero. Let the product of these two rational numbers be represented by "P".
P = (a/b)×(c/d)
P = (a×c)/(b×d)
The numerator is again an integer. The denominator is also a non-zero integer. Hence, the product is a rational number.
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6.0 because if it is 0-4, you round down and 5-9, round up
Answer:
My best answer. Hope this helps...
Step-by-step explanation:
You can see 1 full square in the triangle.
There are also 3 half squares.
The top part of the triangle also equals to 1 half square.
On the bottom right side, you have two shapes that add up to a square.
4 half squares = 2 full squares.
2 + 1 + 1 = 4
The square also has 4 squares.
Your answer would be -35.
Answer:
$78
Step-by-step explanation:
To find a portion of anything, you just multiply your first item by the equivalent decimal of your percent. Let's put it into action in this problem:
If your original price of your bike is $130, and you are trying to find the sale price, which is 60% (aka 0.6) of your original price. Now, like I previously mentioned, to find the portion of your price, you just want to multiply your OG price (130) by the decimal equivalent of your sale, (0.6). So 130*0.6=78
