MARKING BRAINLIEST <br> find a nice three terms of the geometric sequence: -3,6,-12,24

Twenty-seven minus of a number (x) is not more than 36. What is the number? A. x > 42 B. x ≥ -6 C. x < 3 D. x ≤ -6

natali 33 [55]

Answer:

B

Step-by-step explanation:

since it hints that it is less than we can see that B gives it to us also it can't be A cuz 42 is greater than 36

so it is B

Brain list plss

5 0

2 years ago

9 4/5 - 2 3/10= write in simplest form

Solnce55 [7]

Can you post your middle school questions in the middle school area...

9 4/5 - 2 3/10 = X
9 8/10 - 2 3/10 = X
7 5/10 = X
7 1/2 is simplest form

7 0

3 years ago

Given Sin x= 0.5, what is cos x?

Svetllana [295]

Sin x = 0.5
sin x = 1/2
sin x = opp/hyp
therefore the ratio of opp/hyp = 1/2, (opp = 1, hyp = 2)

Find the opp side

1² + x² = 2²
1 + x² = 4
x² = 4 -1
x² = 3
x =√3

The opp side is √3

cos x = opp/hyp = √3/2 = 0.87 (round to the nearest hundredths)

3 0

2 years ago

10 & 11 WILL GIVE BRAINLIST

ra1l [238]

Answer:

10)$38.50

11)D

Step-by-step explanation:

10) n = no. of rides

f(n) + g(n) = 1 + 2.5n

when n=15, 1 + 2.5(15)

= $38.50

11)f(x) = 4x³+3x²-5x+20

g(x) = 9x³-4x²+10x-55

(g-f)(x)=9x³-4x²+10x-55-(4x³

+3x²-5x+20)

= 9x³-4x²+10x-55-4x³

-3x²+5x-20

= 5x³-7x²+15x-75

(Correct me if i am wrong)

3 0

3 years ago

Read 2 more answers

41% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the

lys-0071 [83]

Answer:

a) 0.2087 = 20.82% probability that the number of U.S. adults who have very little confidence in newspapers is exactly five.

b) 0.1834 = 18.34% probability that the number of U.S. adults who have very little confidence in newspapers is at least six.

c) 0.3575 = 35.75% probability that the number of U.S. adults who have very little confidence in newspapers is less than four.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have very little confidence in newspapers, or they do not. The answers of each adult are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

41% of U.S. adults have very little confidence in newspapers.

This means that $p = 0.41$

You randomly select 10 U.S. adults.

This means that $n = 10$

(a) exactly five

This is $P(X = 5)$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{10,5}.(0.41)^{5}.(0.59)^{5} = 0.2087$

0.2087 = 20.82% probability that the number of U.S. adults who have very little confidence in newspapers is exactly five.

(b) at least six

This is:

$P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{10,6}.(0.41)^{6}.(0.59)^{4} = 0.1209$

$P(X = 7) = C_{10,7}.(0.41)^{7}.(0.59)^{3} = 0.0480$

$P(X = 8) = C_{10,8}.(0.41)^{8}.(0.59)^{2} = 0.0125$

$P(X = 9) = C_{10,9}.(0.41)^{9}.(0.59)^{1} = 0.0019$

$P(X = 10) = C_{10,10}.(0.41)^{10}.(0.59)^{0} = 0.0001$

Then

$P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.1209 + 0.0480 + 0.0125 + 0.0019 + 0.0001 = 0.1834$

0.1834 = 18.34% probability that the number of U.S. adults who have very little confidence in newspapers is at least six.

(c) less than four.

This is:

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.41)^{0}.(0.59)^{10} = 0.0051$

$P(X = 1) = C_{10,1}.(0.41)^{1}.(0.59)^{9} = 0.0355$

$P(X = 2) = C_{10,2}.(0.41)^{2}.(0.59)^{8} = 0.1111$

$P(X = 3) = C_{10,3}.(0.41)^{3}.(0.59)^{7} = 0.2058$

So

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0051 + 0.0355 + 0.1111 + 0.2058 = 0.3575$

0.3575 = 35.75% probability that the number of U.S. adults who have very little confidence in newspapers is less than four.

5 0

2 years ago

MARKING BRAINLIEST find a nice three terms of the geometric sequence: -3,6,-12,24