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melomori [17]
3 years ago
14

In a rhombus whose side measures 36 and the smaller angle is 32°, find the length of the larger diagonal, to the nearest tenth.

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
3 0
Given side length "a" and angle "A", calculate the diagonals<span><span>
p = square root [( 2a^2 - 2a^2 cos(A) )]
</span>q = </span><span>square root [( 2a^2+ 2a^2 cos(A) )]</span>
http://www.calculatorsoup.com/calculators/geometry-plane/rhombus.php

side = 36
cos (32) = 0.84805
p = <span>small diagonal = </span> <span> <span> <span> 19.8457652914 </span> </span> </span> <span><span> </span> </span>
q = large diagonal = <span> <span> <span> 69.2108777578 </span> </span> </span>


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  see attached

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