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3 years ago

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In a rhombus whose side measures 36 and the smaller angle is 32°, find the length of the larger diagonal, to the nearest tenth.

1 answer:

Anvisha [2.4K]3 years ago

3 0

Given side length "a" and angle "A", calculate the diagonals<span><span>
p = square root [( 2a^2 - 2a^2 cos(A) )]
</span>q = </span><span>square root [( 2a^2+ 2a^2 cos(A) )]</span>
http://www.calculatorsoup.com/calculators/geometry-plane/rhombus.php

side = 36
cos (32) = 0.84805
p = <span>small diagonal = </span> <span> <span> <span> 19.8457652914 </span> </span> </span> <span><span> </span> </span>
q = large diagonal = <span> <span> <span> 69.2108777578 </span> </span> </span>

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Can someone please help me solve this? <br><br> 2x+5y=-1 <br><br> -10x-25y=5

fredd [130]

this is system of equations

2x + 5y = -1 times this one by 5 to make the y's opposite

-10x -25y = 5

10x - 25y = -5 (this is it times by 5, now add them)

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0 + 0 = 0

now since everything cancels and both sides are equal it has infinite solutions beaus they are actually the same line.

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3 years ago

Given the sequence 2, 5, 8, 11, 14, ..., which term is 59? (Hint: find n.)

____ [38]

N = 3 ( the next number is 3 plus the previous number
sequence formula = an = 3(n-1) +2

so for term the term that =59

59 = 3(n-1) +2

distribute:
59 = 3n -3+2

59 = 3n -1

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3 years ago

Please help extra points cuz ik this will be hard and some time to do

vesna_86 [32]

Answer

Part A

1 - 1

2 - 3

3 - 6

4 - 10

5 - 15

Part B

Now plot these points on the coordinate plane

(1,1) (2,3) (3,6) (4,10) (5,15)

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3 years ago

Read 2 more answers

PLEASE HELP ASAP PLEASE

emmainna [20.7K]

Answer:

The equation that represents the line passing through the point (2, -4) with a slope of one half is

$f(x) = \frac{1}{2}x - 5$

Step-by-step explanation:

The equation of a line can be described by a first order equation in the following format:

$f(x) = ax + b$

In which a is the slope of the line.

Solution:

The line slope is $\frac{1}{2}$ , so $a = \frac{1}{2}$ .

The equation of the line now is:

$f(x) = \frac{1}{2}x + b$

The problem states that the line passes through the point(2,-4). This means that when x = 2, f(x) = -4

So:

$f(x) = \frac{1}{2}x + b$

$-4 = \frac{1}{2}*(2) + b$

$-4 = 1 + b$

$b = -5$

So, the equation that represents the line passing through the point (2, -4) with a slope of one half is

$f(x) = \frac{1}{2}x - 5$

3 0

3 years ago

Given: Q=7m+3n,R=11-2m,s=n+5,and T =-m-3n+8 simplify Q-[R+S]-T

Gnesinka [82]

Answer:

Simplify

$Q-[R+S]-T$

The answer is:

$10m+5n-24$

Step-by-step explanation:

We have the expressions:

$Q=7m+3n\\R=11-2m\\S=n+5\\T=-m-3n+8$

Now, we need simplify:

$Q-[R+S]-T$

We need to replace each term by the expressions:

$7m+3n-[(11-2m)+(n+5)]-(-m-3n+8)$

We need to remember the rule of signs:

$-/-=+$

$-/+=-$

$+/+=+$

With this in mind we solve the parentheses:

$7m+3n-[(11-2m)+(n+5)]-(-m-3n+8)$

$7m+3n-[11-2m+n+5]+m+3n-8$

$7m+3n-11+2m-n-5+m+3n-8$

let's group common terms

$7m+3n-11+2m-n-5+m+3n-8\\7m+2m+m+3n-n+3n-11-5-8$

We must add and subtract common terms:

$7m+2m+m+3n-n+3n-11-5-8\\10m+5n-24$

The answer is:

$10m+5n-24$

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3 years ago