Question

In a rhombus whose side measures 36 and the smaller angle is 32°, find the length of the larger diagonal, to the nearest tenth.

Answer 1

Given side length "a" and angle "A", calculate the diagonals
p = square root [( 2a^2 - 2a^2 cos(A) )]
q = square root [( 2a^2+ 2a^2 cos(A) )]
http://www.calculatorsoup.com/calculators/geometry-plane/rhombus.php

side = 36
cos (32) = 0.84805
p = small diagonal =  19.8457652914
q = large diagonal = 69.2108777578