Answer:
(x + 7)2 + (y + 1)2 = r2.
To get we use point (8, 7): (8 + 7)2 + (7 + 1)2 = r2, r2 = 225 + 64 = 289 = 172.
So, equation of circle: (x + 7)2 + (y + 1)2 = 289
Step-by-step explanation:
True it is true because you can reach the vertext at all times try it out my teacher told me right now check it our
<span>Each team in the softball league plays each of the other teams exactly once. For every game, there is 2 team playing. The order is not important because A vs B is same as B vs A
So you just need to makes a combination of 2 that have a result of 21. If there is t number of teams, the number of matches would be:
tC2 = t!/2!(t-2)! = 21
</span>t! / (t-2)! = 21 *2
(t)(t-1)= 42
t^2 -t -42=0
(t-7)(t+6)
t=7 ; t=-6
Excluding the minus result, you got 7 teams.
Answer:
Put a dot on -1. Go down 5 and then 3 to the right. You will have two points which is enough to make a line. Grab a ruler and connect both of them. You have the line y=-5/3x-1 graphed
Step-by-step explanation:
Answer:
Correct integral, third graph
Step-by-step explanation:
Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.
Given : ∫ tan²(θ)sec²(θ)dθ
Applying u-substitution : u = tan(θ),
=> ∫ u²du
Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1
Substitute back u = tan(θ) : tan^2+1(θ)/2+1
Simplify : 1/3tan³(θ)
Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.
