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labwork [276]
2 years ago
13

Y=5cos(20x) find amplitude, period & graph

Mathematics
1 answer:
bagirrra123 [75]2 years ago
5 0
Amplitude is 5
period is 360/20 = 18 degree
Im lazy to do graph
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Identify the cross section that results from slicing the three-dimensional figure.
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Well a cylinder is the only 3 dimensional shape given so that might be it

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Andrew has 2 / 3 liter of juice. He wants to pour it into 6 smaller containers, putting the same amount in each container. How m
NikAS [45]

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1/9

Step-by-step explanation:

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2 years ago
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Solve each equation you must use
n200080 [17]

1) The solution for m² - 5m - 14 = 0 are x=7 and x=-2.

2)The solution for b² - 4b + 4 = 0 is x=2.

<u>Step-by-step explanation</u>:

The general form of quadratic equation is ax²+bx+c = 0

where

  • a is the coefficient of x².
  • b is the coefficient of x.
  • c is the constant term.

<u>To find the roots :</u>

  • Sum of the roots = b
  • Product of the roots = c

1) The given quadratic equation is m² - 5m - 14 = 0.

From the above equation, it can be determined that b = -5 and c = -14

The roots are -7 and 2.

  • Sum of the roots = -7+2 = -5
  • Product of the roots = -7\times2 = -14

The solution is given by (x-7) (x+2) = 0.

Therefore, the solutions are x=7 and x= -2.

2) The given quadratic equation is b² - 4b + 4 = 0.

From the above equation, it can be determined that b = -4 and c = 4

The roots are -2 and -2.

  • Sum of the roots = -2-2 = -4
  • Product of the roots = -2\times-2 = 4

The solution is given by (x-2) (x-2) = 0.

Therefore, the solution is x=2.

5 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
irga5000 [103]

Answer:

The rocket hits the ground at a time of 11.59 seconds.

Step-by-step explanation:

The height of the rocket, after x seconds, is given by the following equation:

y = -16x^2 + 177x + 98

It hits the ground when y = 0, so we have to find x for which y = 0, which is a quadratic equation.

Finding the roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

y = -16x^2 + 177x + 98

-16x^2 + 177x + 98 = 0

So

a = -16, b = 177, c = 98

\bigtriangleup = 177^{2} - 4(-16)(98) = 37601

x_{1} = \frac{-177 + \sqrt{37601}}{2*(-16)} = -0.53

x_{2} = \frac{-177 - \sqrt{37601}}{2*(-16)} = 11.59

Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.

4 0
3 years ago
What is the domain of this table X 1 2 3 4 Y 2 4 3 2
Hoochie [10]
1,2,3,4 are the domain. The x column is always the domain.
3 0
3 years ago
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