1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
neonofarm [45]
4 years ago
13

What is $700 simple interest ? 7% 7 years 5

Mathematics
1 answer:
Tresset [83]4 years ago
7 0

Answer:

7%

Step-by-step explanation:

TRUST ME I've seen that question and i got it rioght this was the answer

PLEASE MARK ME AS BRAINLIEST!!! I WORKED SO HARD FOR THIS PROBLEM

You might be interested in
∜64= 4ˣ, what is the value of x?
svlad2 [7]

Answer:

x = (2 i π n)/log(4) + log(2 sqrt(2))/log(4) for n element Z

Step-by-step explanation:

Solve for x:

2 sqrt(2) = 4^x

Hint: | Reverse the equality in 2 sqrt(2) = 4^x in order to isolate x to the left hand side.

2 sqrt(2) = 4^x is equivalent to 4^x = 2 sqrt(2):

4^x = 2 sqrt(2)

Hint: | Eliminate the exponential from the left hand side.

Take the logarithm base 4 of both sides:

Answer:x = (2 i π n)/log(4) + log(2 sqrt(2))/log(4) for n element Z

8 0
3 years ago
I need help yall help me
irga5000 [103]

Answer:

Step-by-step explanation:

answer is c

7 0
3 years ago
Which choice is equivalent to the expression below ? <br> 3^7.869
inna [77]
The second one:
3^7 x 3^(86/10) x 3^(9/1000)
That is because when you multiply powers with the same base ( in this case they are all 3), you just leave the base as it is and add the exponents
so it is basically 3^(7 + 86/100 + 9/1000) which is 3^7.869
6 0
3 years ago
Read 2 more answers
Which of the following lists is ordered from least to greatest?
lisabon 2012 [21]

Answer:

-5,0,0.8,1,1 is the answer

4 0
3 years ago
A ball is kicked 4 feet above the ground with an initial vertical velocity of 55 feet per second. The function h(t)=−16t2+55t+4
kramer

<u>Given</u>:

A ball is kicked 4 feet above the ground with an initial vertical velocity of 55 feet per second.

The function h(t)=-16t^2+55t+4 represents the height h(in feet) of the ball after t seconds.

We need to determine the time of the ball at which it is 30 feet above the ground.

<u>Time:</u>

To determine the time that it takes for the ball to reach a height of 30 feet above the ground, let us substitute h(t) = 30, we get;

30=-16t^2+55t+4

26=-16t^2+55t

Adding both sides of the equation by 16t², we get;

16t^2+26=55t

Subtracting both sides of the equation by 55t, we have;

16t^2-55t+26=0

Let us solve the quadratic equation using the quadratic formula, we get;

t=\frac{-(-55) \pm \sqrt{(-55)^2-4(16)(26)}}{2(16)}

t=\frac{55 \pm \sqrt{3025-1664}}{32}

t=\frac{55 \pm \sqrt{1361}}{32}

t=\frac{55 \pm 36.89}{32}

t=\frac{55 + 36.89}{32} \ or \ t=\frac{55- 36.89}{32}

t=\frac{91.89}{32} \ or \ t=\frac{18.11}{32}

t=2.9 \ or \ t=0.6

The value of t is t = 0.6 because this denotes the time taken by the ball to reach a height of 30 feet from the ground.

Therefore, the time taken by the ball to reach a height of 30 feet above the ground is 0.6 seconds.

5 0
3 years ago
Other questions:
  • Preston is making cookies. He has fraction 4 over 5 cups of flour in a bag. He then used two fractions 1 over 10 cup scoops of f
    13·2 answers
  • Compute using long division: 1,234÷68
    15·1 answer
  • What are the common factors for 88 and 24
    11·1 answer
  • The coordinates of point A on the coordinate grid are (-2-3) point A reflected across the y-axis to obtain point B and across th
    14·1 answer
  • What is 130%of20$???!!!!!
    14·2 answers
  • Can you solve (4x-3)/(x+2)+(15)/(x-3)
    13·2 answers
  • What are the answers to this someone please help.
    7·1 answer
  • What are the dependent (y) and the independent (x) variables?
    11·1 answer
  • Which of the following is equivalent to 0 equals 3 x squared minus 12 x minus 15 when completing the square?
    7·1 answer
  • Help me find a ordered pair
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!