<em>Answer:</em>
<em />
<em>x³ + x² - 6x = 0</em>
<em>x(x² + x - 6) = 0</em>
<em>x(x² + 3x - 2x - 6) = 0</em>
<em>x[x(x + 3) - 2(x + 3)] = 0</em>
<em>x(x - 2)(x + 3) = 0</em>
<em>x₁ = 0</em>
<em>x - 2 = 0 => x₂ = 2</em>
<em>x + 3 = 0 => x₃ = - 3</em>
Step-by-step explanation:
REALLLYYY???!!!!!!
JK
thx 4 the points..
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Given :
- The length of a rectangle is 4m more than the width.
- The area of the rectangle is 45m²
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To Find :
- The length and width of the rectangle.
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Solution :
We know that,
So,
Let's assume the length of the rectangle as x and the width will be (x – 4).
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Now, Substituting the given values in the formula :
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Since, The length can't be negative, so the length will be 9 which is positive.
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Hello!
First of all, 6 and 10 are not prime numbers as they both have at least two pairs of factors (one factor pair plus one and itself).
Anything multiplied by two is even. Therefore, a) 2 counterexamples the statement. Just to show why 7 doesn't work, seven multiplied by 3 is 21, which is odd, and 7 times 7 is 49, and 7 times 5 is 35 (all prime multipliers). The only one that works is two.
I hope this helps!
