53= -19z+5+7z
53= -12z+5 (combine -19z and 7z)
48= -12z. ( subract 5 on both sides)
-4=z. (divide by -12 both sides)
Answer:
There are 260 seats in economy class and 100 seats in business class
Step-by-step explanation:
To solve this problem we first have to calculate the fraction of economic and business seats with respect to the total
We are told that every 13 seats in economy class there are 5 seats in business class
13 + 5 = 18
This means that if there are 18 seats 13 will be economic and 5 business
economic seats = 13/18
business seats = 5/18
To find out the number of seats in the airplane of each class, we have to multiply the total number of seats by these fractions
economic seats = 360 * 13/18
economic seats = 260
business seats = 360 * 5/18
business seats = 100
Answer:
x=24
Step-by-step explanation:
We can set up an equation:
2/3 * x = 16
Multiplying both sides by the reciprocal of 2/3 to isolate the variable, we get
3/2 * 2/3 * x = 16* 3/2
1*x=24
x=24
Non proportional~
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